All categories

3 years ago

ANSWER ASAP thanks

Chemistry

2 answers:

Lady_Fox [76]3 years ago

6 0

Answer:

Its D

Explanation:

I Did It on Edge2020

weqwewe [10]3 years ago

5 0

Answer:

Option D: it's ability to lose electrons

Explanation:

Alkali metals are usually discovered in nature. They have highly reactivity at STP conditions (standard temperature and pressure conditions) and easily lose their outermost electron to form positive ions known that have a charge of +1.

Thus, what can determine the extent of reactivity of an alkali metal, is it's ability to lose electrons

You might be interested in

What is a round body of water formed by a glacier?

photoshop1234 [79]

Its usually referred to as a glacial lake.

5 0

3 years ago

The colour imparted to a flame by calcium ion?

igor_vitrenko [27]

I not sure, but i know that is soft yellow no white not yellow.

7 0

3 years ago

A 100.0-mL flask contains 0.193 g of a volatile oxide of nitrogen. The pressure in the flask is 760 mmHg at 17°C. Is the gas NO,

cestrela7 [59]

Answer:

$NO_2$

Explanation:

Considering,

$n=\frac{m}{M}$

Using ideal gas equation as:

$PV=\frac{m}{M}RT$

where,

P is the pressure = 760 mmHg

V is the volume = 100.0 mL = 0.1 L

m is the mass of the gas = 0.193 g

M is the molar mass of the gas = ?

Temperature = 17 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (17 + 273.15) K = 290.15 K

R is Gas constant having value = 62.36367 L. mmHg/K. mol

Applying the values as:-

$760\times 0.1=\frac{0.193}{M}\times 62.36367\times 290.15$

M = 45.95 g/mol

This mass corresponds to $NO_2$ . Hence, the gas must be $NO_2$ .

7 0

3 years ago

The change in frequency of a wave acceleration

nikdorinn [45]

Answer:

it decreases the amplitude of the wave as it propagates

Explanation:

5 0

3 years ago

The Environmental Protection Agency has determined that safe drinking

dmitriy555 [2]

Answer:

b) $\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$

The confidence interval for this case is given (6.21, 6.59)

So we can conclude at 95% of confidence that the true mean for the PH concentration is between 6.21 and 6.59 moles per liter

c) Since the confidence interval not contains the value 7 we reject the hypothesis that the true mean is equal to 7. And the same result was obtained with the t test for the true mean.

Explanation:

We assume that part a is test the claim. And we can conduct the following hypothesis test:

Null hypothesis: $\mu =7$

Alternative hypothesis $\mu \neq 7$

The statistic is to check this hypothesi is given by:

$t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

We know the following info from the problem:

$\bar X = 6.4 , s=0.5, n =30$

Replacing we got:

$t = \frac{6.4-7}{\frac{0.5}{\sqrt{30}}}= -6.573$

And the p value would be:

$p_v= 2*P(Z$

Since the p value is very low compared to the significance assumed of 0.05 we have enough evidence to reject the null hypothesis that the true mean is equal to 7 moles/liter

Part b

The confidence interval is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$

The confidence interval for this case is given (6.21, 6.59)

So we can conclude at 95% of confidence that the true mean for the PH concentration is between 6.21 and 6.59 moles per liter

Part c

Since the confidence interval not contains the value 7 we reject the hypothesis that the true mean is equal to 7. And the same result was obtained with the t test for the true mean.

6 0

3 years ago