Answer:
She will need to add 5.6 cups of water
Explanation:
Hi there!
Marta has to dilute the citric acid to 5%.
The dilution factor will be 12%/ 5% = 2.4. Then, Marta will need to dilute the citric acid 2.4 times. If she has 4 cups of the solution, she will need to add water until she completes a volume of (4 cups ·2.4) 9.6 cups to reach the desired concentration.
Then, she will need to add 9.6 - 4 cups water = 5.6 cups of water
Another way to solve this is by using the fact that the mass of citric acid in the concentrated and diluted solution is the same. Then:
mass citric acid concentrated solution = mass citric acid in dilute solution
mass of citric acid = concentration · volume
Then:
initial concentration · volume = final concentration · volume
12% · 4 cups = 5% · volume
volume = 12% · 4 cups / 5% = 9.6 cups
The final volume of the solution at 5% will be 9.6 cups. So Marta will need 9.6 cups - 4 cups = 5.6 cups water
Answer:
1. Chemical Equation 2. Reactants 3. Products 4. Coefficients 5. Balance 6. Conservation 7. Equal 8. Created 9. Destroyed 10. Coefficients 11. Subscripts
Explanation:
Answer:
0.35 milli moles of ethanol can be theoretically be produced under these conditions.
Explanation:
Moles of glucose = 
milli mole
Moles of ADP = 0.35 milli mole
Moles of Pi = 0.35 milli mole
Moles of ATP = 0.70 milli mole
As we can see that ADP and Pi are in limiting amount which means tat they are limiting reagent. So, the moles of ethanol produced will depend upon the moles of ADP and Pi.
According to reaction, 2 moles of ADP gives 2 moles of glucose.
Then 0.35 milli moles of ADp will give :
of ethanol
0.35 milli moles of ethanol can be theoretically be produced under these conditions.
