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lesantik [10]
3 years ago
15

Find the rate of heat transfer through a 6 mm thick glass window with a cross-sectional area of 0.8 m2 if the inside temperature

is 310 K and the outside temperature is 265 K. The thermal conductivity of glass is (0.9 J/s m K )
Engineering
1 answer:
kiruha [24]3 years ago
3 0

Answer:

6.9

Explanation:

I had the same question lol your welcomr if itd not right in sorry

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A fiberglass composite is composed of a matrix of vinyl ester and reinforcing fibers of E-glass. The volume fraction of E-glass
masha68 [24]

Full Question

Calculate the modulus of elasticity of the composite

I. In the longitudinal direction of the glass fibre

2. In the perpendicular direction of glass fibre

Answer:

1. 27.5876 GPa

2. 5.725 GPa

Explanation:

Given

Dimensions of the fibreglass is given by: 1.00 cm x 25.00 cm x 200.00 cm

Volume = 1 * 25 * 200 = 5000cm³

P1 = The volume fraction of the E-glass is 31%

P2 = The remainder 69% is Vinyl Ester

Volume of Vinyl Ester= 69% * 5000cm³ = 3450cm³

I. In the longitudinal direction of the glass fibre

Where

Modulus of elasticity of glass, E1 = 80 Gpa

Modulus of elasticity of vinyl ester, E2 = 4.04 Gpa

Modulus of elasticity = E1P1 + E2P2

Modulus of elasticity of vinyl esters = 31% * 80 + 69% * 4.04

Modulus = 24.8 + 2.7876

Modulus = 27.5876 GPa

ii. In the perpendicular direction of glass fibre

This is solved by

E1.E2/(P1.E2 + P2.E1)

= (80 * 4.04)/(31% * 4.04 + 69% * 80)

= 323.2/(1.2524 + 55.2)

= 5.725177317527687

= 5.725 GPa

7 0
3 years ago
_______________ is an effective way to manage waste in a shop.
Murrr4er [49]

Answer:

To reduce waste.

Explanation:

3 0
3 years ago
A specimen of 4340 Steel Tempered at 425 C is being tested using a single edge notched tension configuration. The estimated Y pa
r-ruslan [8.4K]

Answer:

length of starter crack = 1.056

Explanation:

given data

temperature = 425 C

yield strength = 60%

Y parameter = 2.5

solution  

we use here A 20 table so we get here value that is

Sy = 1360 MPa

Kic = 117.5 MPa \sqrt{m}

so length of starter crack  will be

a = \frac{1}{\pi } (\frac{Kic}{Y\times \sigma max})^2     .....................1

put here value and we will get

a =  \frac{1}{\pi } (\frac{117.5}{2.5\times 0.6 \times 1360})^2  

solve it we get

length of starter crack = 1.056

5 0
3 years ago
A blizzard is a massive snowstorm. Definitions vary, but for our purposes, we will assume that a blizzard is characterized by bo
natali 33 [55]

Answer:

The weather conditions do not suggest a blizzard. It is explained below.

Explanation:

wind_speed=randi([12 56],24,1);

visibility=randi([1 10],24,1)/10;

storm_data=[wind_speed,visibility];

save stormtrack.dat storm_data -ascii

clear

load stormtrack.dat

fprintf('Below is the storm data from the file stormtrack.dat \n');

disp(stormtrack)

wind_speed=stormtrack(:,1);

visibility=stormtrack(:,2);

L=length(wind_speed);

count=0;

i=0;

while count<4 && i<L

i=i+1;

if wind_speed(i)>=30 && visibility(i)<=0.5

count=count+1;

else

count=0;

end

end

if count==4

fprintf('The weather conditions suggest a blizzard.\n')

else

fprintf('The weather conditions do not suggest a blizzard.\n')

end

Results:

Below is the storm data from the file stormtrack.dat  

49.0000 0.1000

56.0000 0.4000

44.0000 0.6000

27.0000 0.7000

38.0000 0.5000

16.0000 0.9000

52.0000 0.8000

1 51.0000 1.0000

48.0000 0.6000

23.0000 0.4000

38.0000 0.2000

13.0000 0.7000

31.0000 0.8000

26.0000 0.5000

19.0000 0.1000

20.0000 0.3000

31.0000 0.2000

16.0000 0.3000

38.0000 0.5000

33.0000 0.6000

43.0000 0.5000

43.0000 0.9000

40.0000 0.6000

13.0000 1.0000

The weather conditions do not suggest a blizzard.

6 0
3 years ago
Where can you find the grade for a piece of property?
Nadya [2.5K]

Answer:

Simply put, the grade or grading around your house is the level of the ground. The ground level and how it's graded is the deciding factor of where storm water will flow.

Explanation:

5 0
3 years ago
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