Explanation:
power output=(1800×10×0.06)/9=120watts
Answer:
a metallic
Explanation:
Metal atoms are joined together by metallic bonds. Metals can form cations (positive ions) with a sea of delocalized electrons.
Energy is the ability to do work or cause change. There are basically
two main types of energy, kinetic and potential. Potential energy is
energy that is stored. There are various types of stored, or potential
energy. Chemical energy from a battery is a potential form of energy,
elastic energy in a stretched rubber band is a form of potential energy,
but the most commonly referred to form of potential energy in physics
is that of gravitational potential energy. This is energy that is
stored due to an object's position. It is dependent on the mass of the
object, the height of the object above the ground or Earth, and the acceleration due to gravity.
The amoeba is having a asexual reproduction and the two birds are not. The two birds are having a sexual reproduction.
Answer:
A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes
Explanation:
Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:
2as = Vf² - Vi²
s = (Vf² - Vi²)/2a
where,
Vf = Final Velocity of Car = 0 mi/h
Vi = Initial Velocity of Car = 50 mi/h
a = deceleration of car
s = distance covered
Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.
So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:
s = vt
FOR SOBER DRIVER:
v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s
t = 0.33 s
s = s₁
Therefore,
s₁ = (73.33 ft/s)(0.33 s)
s₁ = 24.2 ft
FOR DRUNK DRIVER:
v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s
t = 1 s
s = s₂
Therefore,
s₂ = (73.33 ft/s)(1 s)
s₂ = 73.33 ft
Now, the distance traveled by drunk driver's car further than sober driver's car is given by:
ΔS = s₂ - s₁
ΔS = 73.33 ft - 24.2 ft
<u>ΔS = 49.13 ft</u>
