2. What is the smallest particle into which an

Which example is NOT a part of the electromagnetic spectrum?

Alekssandra [29.7K]

Electricity is NOT a part of electromagnetic spectrum.

An electromagnetic spectrum contains electromagnetic radiations arranged according to frequencies and wavelength.

<h2>Further Explanation </h2><h3>Electromagnetic waves </h3>

Electromagnetic waves are types of waves that do not require a material medium for transmission.
These waves are mostly transverse in nature, which means the direction of transmission is perpendicular to the direction of vibration of particles.
They include, light waves, radio waves, x-rays, infra-red, etc.

<h3>Electromagnetic spectrum </h3>

An electromagnetic wave shows electromagnetic waves arranged according to frequencies and wavelength.
Electromagnetic spectrum contains electromagnetic waves: Gamma rays, x-rays, Ultraviolet, Visible light, infra-red, microwaves, and radio waves.
The electromagnetic spectrum is divided into various sections based on wavelength, with gamma rays having the shortest wavelength and radio waves having the longest wavelength.
The part of the electromagnetic spectrum that we can see using our naked eyes is called the visible light spectrum.
In order of frequency, the radio waves have the lowest frequency while gamma rays have the largest frequency.

<h3>General characteristics of electromagnetic waves </h3>

They travel with the speed of light (3.0 x 10^8 m/s)
They possess energy that is given by; E =hf, where h is the plank’s constant and f is the frequency.
They are transverse in nature, and therefore, the wavelength is measured between successful crests or troughs.
They can travel through vacuum

Keywords: Electromagnetic spectrum, electromagnetic waves.

<h3>Learn more about: </h3>

Electromagnetic spectrum: brainly.com/question/11725209
Electromagnetic waves: brainly.com/question/12450147
Characteristics of electromagnetic waves: brainly.com/question/12450147

Level: High school

Subject: Physics

Topic: Electromagnetic spectrum

8 0

3 years ago

Read 2 more answers

Determine the angle of an incline that would yield a constant velocity, given the coefficient of kinetic friction is 0.10.

azamat

Answer:

$\theta=5.71^{o}$

Explanation:

In order to solve this problem, we mus start by drawing a free body diagram of the given situation (See attached picture).

From the free body diagram we can now do a sum of forces in the x and y direction. Let's start with the y-direction:

$\sum F_{y}=0$

$-W_{y}+N=0$

$N=W_{y}$

so:

$N=mgcos(\theta)$

now we can go ahead and do a sum of forces in the x-direction:

$\sum F_{x}=0$

the sum of forces in x is 0 because it's moving at a constant speed.

$-f+W_{x}=0$

$-\mu_{k}N+mg sen(\theta)=0$

$-\mu_{k}mg cos(\theta)+mg sen(\theta)=0$

so now we solve for theta. We can start by factoring mg so we get:

$mg(-\mu_{k} cos(\theta)+sen(\theta))=0$

we can divide both sides into mg so we get:

$-\mu_{k} cos(\theta)+sen(\theta)=0$

this tells us that the problem is independent of the mass of the object.

$\mu_{k} cos(\theta)=sen(\theta)$

we now divide both sides of the equation into $cos(\theta)$ so we get:

$\mu_{k}=\frac{sen(\theta)}{cos(\theta)}$

$\mu_{k}=tan(\theta)$

so we now take the inverse function of tan to get:

$\theta=tan^{-1}(\mu_{k})$

so now we can find our angle:

$\theta=tan^{-1}(0.10)$

so

$\theta=5.71^{o}$

8 0

3 years ago

A model rocket is shot directly upward, rises to its maximum height and then returns to its launch position in 10.0 s. Assuming

worty [1.4K]

d. 49.0 m/s

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3 0

3 years ago

Jane and John Doppler effect

UkoKoshka [18]

Answer:

To summarize, Jane's star has a red light and is traveling towards the Earth while John's star has a blue light and is traveling away from the Earth. This is a prime example of the Doppler Effect in motion. The stars look different because they are traveling in different directions.

4 0

3 years ago

A man's higher initial acceleration means that a man can outrun a horse over a very short race. A simple - but plausible - model

Lera25 [3.4K]

Answer:

t_man = 10.16 s, t_horse = 10.73 s, the winner is the man

Explanation:

To solve this problem we are going to find the time of each one separately.

Man we look for distance and time during acceleration

x₁ = v₀ t₁ + ½ a₁ t₁²

as it comes out of rest its initial velocity is zero

x₁ = ½ a₁ t₁²

x₁ = ½ 6.0 1.8²

x₁ = 9.72 m

at this point its speed is

v₁ = v₀ + a t

v₁ = 0 + 6 1.8

v₁ = 10.8 m / s

From here on it continues at constant speed, the distance that the man needs to travel from the point where the man leaves at 100m is

x₂ = 100 - x₁

x₂ = 100- 9.72

x₂ = 90.28 m

the time for this part is

v₁ = x₂ / t₂

t₂ = x₂ / v₂

t₂ = 90.28 / 10.8

t₂ = 8.36 s

the total time for the man is

t_man = t₁ + t₂

t _man = 1.8 + 8.36

t_man = 10.16 s

We repeat the calculation for the horse

distance traveled during the acceleration period

x₃ = v₀ t + ½ a₂ t₃²

as part of rest its initial velocity is zero

x₃ = ½ a₂ t₃²

x₃ = ½ 5.0 4.8²

x₃ = 57.6 m

the velocity at this point is

v₃ = v₀ + a₂ t₃

v₃ = 0 + 5 4.8

v₃ = 24 m / s

the rest of the route is at constant speed, the remaining distance

x₄ = 200 - x₃

x₄ = 200 - 57.6

x₄ = 142.4 m

the time to go through it is

t₄ = x₄ / v₃

t₄ = 142.4 / 24

t₄ = 5.93 s

the total time for the horse is

t_horse = t₃ + t₄

t_horse = 4.8 + 5.93

t_horse = 10.73 s

when we compare the times we see that the man arrives a little before the horse, the winner is the man

5 0

3 years ago