Answer:
Option D: 1.5in in front of the target
Explanation:
The object distance is 
.
Because the surface is flat, the radius of curvature is infinity .
The incident index is 
and the transmitted index is 
.
The single interface equation is 
Substituting the quantities given in the problem,
The image distance is then 
Therefore, the coin falls 
in front of the target
Well it depends it has to be some kind of metal material if not then it will not pick it up Hope this helps:)
Answer:
a) 323.4J
b) 0J
c) -323.4J
Explanation:
a) W=Fd
F=ma
solve for acc. using kinematics
v^2=vo^2+2a(x)
8.41=2a(12)
4.205=a(12)
0.35=a
F=(77)(0.35)
F=26.95N
W=26.95*12...... W=323.4J
b) No acceleration, thus no force, thus no work!
c) W=Fd
F=ma
find acc. using kinematics: v^2=vo^2+2a(x)
0=(2.9^2)+2a(12)
0=8.41+2a(12)
-8.41=2a(12)
-4.205=a(12)
-0.35=a
F=(77)(-0.35)
F=-26.95N
W=(-26.95)(12)
W=-323.4J
Yes, work can be negative!
<span>Force F = 280 N
Angle with the ground = 40 degrees
Weight of the Lawnmower = 350 N
Velocity is constant so Acceleration is 0
So Forward force Ff = F cos theta = 280 cos40
Frictional force with resists to back Fb = (u x Force from pressure) + vertical component of Force, where u is the coefficient of friction.
Fb = (u x m x g) + (u x 280sin40)
AS Ff = Fb => 280 cos40 = u x ((m x g) + 280sin40)
u = 280 cos40 / ((350 x 9.81) + 280sin40) = 214.49 / () = 0.405
So the coefficient of friction u = 0.405</span>
Answer: The buoyant force acting upwards on the crate is smaller than the downward force of gravity on the crate. The crate will sink and accelerate downwards
Explanation:
At any moment, while the crate remains submerged in water, there are two external forces acting on the crate: the gravity force (in this case, 30 N), that aims always downward, and the buoyant force, due to the water removed by the crate while it is being submerged, which is always upwards.
As in this case the buoyant force is smaller than the weight of the crate, there is a net force pointing downward, causing the object to sink and accelerate downwards in order to be compliant with Newton's 2nd Law.
