Answer:
The concentration the student should write down in her lab is 2.2 mol/L
Explanation:
Atomic mass of the elements are:
Na: 22.989 u
S: 32.065 u
O: 15.999 u
Molar mass of sodium thiosulfate, Na2S2O3 = (2*22.989 + 2*32.065 + 3*15.999) g/mol = 158.105 g/mol.
Mass of Na2S2O3 taken = (19.440 - 2.2) g = 17.240 g.
For mole(s) of Na2S2O3 = (mass taken)/(molar mass)
= (17.240 g)/(158.105 g/mol) = 0.1090 mole.
Volume of the solution = 50.29 mL = (50.29 mL)*(1 L)/(1000 mL)
= 0.05029 L.
To find the molar concentration of the sodium thiosulfate solution prepared we use the formula:
= (moles of sodium thiosulfate)/(volume of solution in L)
= (0.1090 mole)/(0.05029 L)
= 2.1674 mol/L
Density is equal to mass over volume.
D = m/v
m = 2.56 kg
V = 0.820 L
D = 2.56 / 0.820
D = <span>3.12195 kg/L which is the density of the liquid.
</span>
Number of moles = 2.12 mol C3H8.
1 mol C3H8 = 6.02 × 1023 molecules C3H8.
<span>1 molecule C3H8 = </span>11 atoms.
(3 carbon atoms<span> and 8 hydrogen atoms)</span>
Answer:
02 is a product
Explanation:
it doesnt take part in chemical reaction so its not reactant.02 doesnt alter rate of chemical reaction so it cannot be catalyst. it is gas it is not solid so it is a product.