The potential difference isV=220−85=135.
Now the potential V at distance d from a point charge Q isV=Q/4πϵ0d
If you solve this for d and plug in the potential difference you will get the answer.
Answer:
The answer is True
Explanation:
Statistical Multiplexing is considered an example of communication link sharing which makes it comparable to DBA (Dynamic Bandwidth Allocation). Here, communication channels are broken down into data streams to optimize the communication process.
In Statistical Time-division Multiplexing, time slots are allocated to data streams for communication optimization. This method makes sure that no time slot or bandwidth is wasted.
Hence, the sum of combined circuits must not be equal to the capacity of the circuit to work effectively.
Answer:
the impulse is 14 kg-m/s and the net force applied is 14000 N
Explanation:
Given that,
The mass of a baseball, m = 0.14 kg
Initial velocity of the baseball, u = -40 m/s
Final velocity, v = 60 m/s
Time, t = 0.001 s
We need to find the impulse and average net force applied to the ball by the bat.
Impulse = change in momentum
i.e.
J = m(v-u)
J = 0.14 × (60-(-40))
J = 14 kg-m/s
Now,
J = Ft
F is average force applied to the ball
So,
So, the impulse is 14 kg-m/s and the net force applied is 14000 N.
Answer:
Explanation:
The refractive index of the lens is
d = 1.570 dioptres
Therefore, her focal length is
f = 1 / d
f = 1 / 1.570
f = 0.6369 m
f = 63.69cm
The distance between the newspapers and her eyes is 42cm
Distance from her eye to the glasses is 2cm
We want to calculate her near point?
So, the distance between the newspaper and the glass
do = 42 - 2 = 40cm
The distance between the glass and the virtual image formed is given as
di = f•do / (do —f)
di = 63.69 × 40 / (40 — 63.69)
di = 2547.6cm / -23.69
di = —107.54cm
The relation use is obtain from the lens equation and the negative shows that virtual image formed.
The near point from her eye is
107.54 + 2 = 109.54cm
A i checked hope i was right