Answer:
a) 8.58 m/s upward
b) -2.211 m/s downward
Explanation:
Let gravitational acceleration g = -9.81m/s2. This is negative because it deceleration the upward motion of the key.
(a)We have the following equation of motion

where
is the initial upward velocity of the keys, t = 1.1s is the time it takes for the keys to travel a distance of s = 3.5 m




So the keys were thrown initially upward with a speed of 8.58 m/s
(b) If the initial velocity of the key is 8.58 m/s and it is subjected to a deceleration of 9.81m/s2 for 1.1s then the velocity right at the 1.1s instant is

So they keys would have a downward speed of 2.211 m/s
To solve this problem we will begin by finding the pressure through density and average depth. Later we will find the Force, by means of the relation of the pressure and the area.

Here,
h = Depth average
= Density
Moreover,

Replacing,


Finally the force



Answer:
B = 0.157 T
Explanation:
Given that,
Length of the solenoid, l = 8 cm = 0.08 m
Number of turns in the wire, N = 2000
Current, I = 5 A
We need to find the strength of the magnetic field at the center of the solenoid. It is given by the formula as follows :
, N is number of turns per unit length of solenoid.
So,

So, the magnetic field at the center of the solenoid is 0.157 T.
Answer:
(a) 
(b) 
(c)
Explanation:
Given data
x(t)=αt²-βt³
α=1.53m/s²
β=0.0480m/s³
First we need to find distance x at these time so
x(t)=1.53t²-0.0480t³
at t=0
x(0)=1.53(0)²-0.0480(0)³=0m
at t=2
x(2)=1.53(2)²-0.0480(2)³=5.736m
at t=4s
x(4)=1.53(4)²-0.0480(4)³=21.408 m
For(a) Average velocity at t=0s to t=2s
The average velocity is given as
Vavg=Δx/Δt

For(b) Average velocity at t=0s to t=4s
The average velocity is given as
Vavg=Δx/Δt

For(c) Average velocity at t=2s to t=4s
The average velocity is given as
Vavg=Δx/Δt
