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Veronika [31]
2 years ago
11

which event would be less widely visible from Earth: a partial lunar eclipse or a total lunar eclipse? explain please

Chemistry
1 answer:
adell [148]2 years ago
6 0

Answer:

I had the same question and I put a total lunar eclipse.

Explanation:

A total lunar eclipse would be less widely visible because, in a partial lunar eclipse the moon only has to partly be in the Earth's shadow.

I don't know if this is helpful or not, but this is what I put if you still needed it.

Still stuck? Get 1-on-1 help from an expert tutor now.

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If you added 45,000 calories to water that was at 25 degrees C, and the ending temperature was 35 degrees C, how much water did
user100 [1]

<u>Answer:</u>

<em>4.5 L water we have in litres (L).</em>

<em><u></u></em>

<u>Explanation:</u>

Q=m\times c \times \Delta T

where

\Delta T = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for water 1.0  cal/(g℃))  

m is the mass of water

Plugging in the values  

\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times\left(35^{\circ} \mathrm{C}-25^{\circ} \mathrm{C}\right)$\\\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}$\\\\$m=\frac{45000 \mathrm{cal}}{1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}}$\\\\$m=4500 \mathrm{g}$\\\\Density of water $=\frac{\text { mass }}{\text { volume }}$

So,

Volume of water = mass/density

\\\\=\frac{4500 \mathrm{g}}{\frac{1.09}{\mathrm{mL}}}=4500 \mathrm{mL}$$

=4.5 L (Answer)

6 0
3 years ago
2C 2 H 6 +7O 2 ***&gt;4CO 2 +6H 2 O if 7.0 g of C 2 H 6 react with 18 g of O 2 , how many grams of water will be produced
Alex787 [66]

Answer:

grams H₂O produced = 8.7 grams

Explanation:

Given 2C₂H₆(g) + 7O₂(g) => 4CO₂(g) + 6H₂O(l)

               7g           18g                             ?g

Plan => Convert gms to moles => determine Limiting reactant => solve for moles water => convert moles water to grams water

Moles Reactants

moles C₂H₆ = 7g/30g/mol = 0.233mol

moles O₂ = 18g/32g/mol = 0.563mol

Limiting Reactant => (Test for Limiting Reactant)  Divide mole value by respective coefficient of balanced equation; the smaller number is the limiting reactant.

moles C₂H₆/2 = 0.233/2 = 0.12

moles O₂/7 = 0.08

<u><em>Limiting Reactant is O₂</em></u>

Moles and Grams of H₂O:

Use Limiting Reactant moles (not division value) to calculate moles of H₂O.

moles H₂O = 6/7(moles O₂) = 6/7(0.562) moles H₂O = 0.482 mole H₂O yield

grams H₂O = (0.482mol)(18g·mol⁻¹) = 8.7 grams H₂O

3 0
3 years ago
Which statement BEST describes why licensed health care workers are held to a higher standard?
strojnjashka [21]

Answer:

They agree to ethical standards when they are licensed.

Explanation:

4 0
3 years ago
What is the word that means litter on the ground or harmful chemicals in the water?
nydimaria [60]
Pollution might be the word you are looking for.

Pollution means the introduction of a substance(s) that is harmful to the environment,
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3 years ago
hoose the best word or phrase to complete each sentence. 1.is a financial service that offers a kind of in the event of unforese
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Medical Insurance and Premium are the answers to your questions.

8 0
3 years ago
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