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2 years ago

10

For each reaction below, use the drop-down menus to select which compound will form a precipitate. Note: It is possible that no

precipitates form.
Na2S + Cd(NO3)2 → CdS + 2NaNO3

FeCl3 + 3KOH → 3KCl + Fe(OH)3

Na2CO3 + Ba(NO3)2 → BaCO3 + 2NaNO3

1 answer:

Dimas [21]2 years ago

8 0

Answer:

1. Cadmium sulfide

2. Iron (III) hrydroxide

3. Barium carbonate

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How many lines does a starfish have in symmetry

Ahat [919]

A starfish has five equal arms, so a starfish would have 5 lines of symmetry. Hope this helps!

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2 years ago

A piece of high-density Styrofoam measuring 24.0 cm by 36.0 cm by 5.0 cm floats when placed in a tub of water. When a 1.5 kg boo

zheka24 [161]

Explanation:

The given data is as follows.

Width of Styrofoam = 24.0 cm

Length of Styrofoam = 36.0 cm

Height of Styrofoam = 5.0 cm

Therefore, volume of the Styrofoam will be calculated as follows.

Volume = length × width × height

= (36.0 × 24.0 × 5.0) $cm^{3}$

= 4320 $cm^{3}$

or, = $4.32 \times 10^{3} cm^{3}$

As Styrofoam partially sinks at 3.0 cm and total height of Styrofoam is 5.0 cm. Hence, height of Styrofoam above the water is (5.0 - 3 cm) = 2 cm.

So, volume of water displaced is as follows.

24.0 cm × 36.0 cm × 2.0 cm

= $1.73 \times 10^{3} cm^{3}$

Hence, mass of displaced water is as follows.

mass = density × volume

= $1.00 g/cm^{3} \times 1.73 \times 10^{3} cm^{3}$

= $1.73 \times 10^{3} g$

Since, book is placed on the Styrofoam. Therefore, mass of water displaced is also equal to the following.

Mass of water displaced = mass of book + mass of Styrofoam

$1.73 \times 10^{3} g$ = 1500 g + mass of Styrofoam

(1730 - 1500) g = mass of Styrofoam

mass of Styrofoam = 230 g

Therefore, calculate the density of Styrofoam as follows.

Density = $\frac{mass}{volume}$

= $\frac{230}{4.32 \times 10^{3} cm^{3}}$

= $53.24 \times 10^{-3} g cm^{-3}$

Thus, we can conclude that the density of Styrofoam is $53.24 \times 10^{-3} g cm^{-3}$ .

4 0

2 years ago

An atom with an atomic number of 10 and a mass number of 24 would have ________.

Anastaziya [24]

An atom with an atomic number of 10 and a mass number of 24 would have 14 neutrons.

<h3>What is atomic number and mass number?</h3>

The term atomic number, conventionally denoted by the symbol Z.

Atomic number indicates the number of protons present in the nucleus of an atom, which is also equal to the number of electrons in an uncharged atom.

The mass number of a given atom is defined by the number of protons and neutrons present in the nucleus. In simple,

Protons + Neutrons = Mass Number

To learn more about atoms, refer

https://brainly.in/question/5318

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6 0

1 year ago

Calculate the number of kilojoules of energy required to convert 50.0 grams of solid DMSO initially at a temperature of 19.0°C t

GuDViN [60]

Answer:

20.79 kilojoules

Explanation:

Using Q = m×c×∆T

Where;

Q = Quantity of heat (J)

c = specific heat capacity of solid DMSO (1.80 J/g°C)

m = mass of DMSO

∆T = change in temperature

According to the provided information, m= 50g, initial temperature = 19.0°C, final temperature= 250.0°C

Q = m×c×∆T

Q = 50 × 1.80 × (250°C - 19°C)

Q = 90 × 231

Q = 20790 Joules

To convert Joules to kilojoules, we divide by 1000 i.e.

20790/1000

= 20.79 kilojoules

Hence, 20.79 kilojoules of energy is required to convert 50.0 grams of solid DMSO to gas.

4 0

2 years ago

What is the maximum amount of water (in grams) that can be removed from 15ml of toluene by the addition?

Nataly [62]

Complete Question

Magnesium sulfate forms a hydrate with the formula $MgSO_4. 7H_20$ . What is the maximum amount of water (in grams) that can be removed from 15 ml of toluene by the addition of 200 mg of anhydrous magnesium sulfate? The molar mass of $MgSO_4$ is 120.4 g/mol; H20 = 18 g/mol.

Answer:

The value is $z = 0.2093 \ g$ of $H_2O$

Explanation:

From the question we are told that

The volume of toluene is $V = 15 mL$

The mass of anhydrous magnesium sulfate is $m = 200m g = 200 *10^{-3} \ g$

The formula of the hydrate is $MgSO_4. 7H_20$

The molar mass of $MgSO_4$ is $z =120.4 \ g/mol$

From the formula given we see that

1 mole of $Mg SO_4$ wil remove 7 moles of $H_2O$ to for the given formula

Hence

120.4 g (1 mole) will remove 7 moles (7 * 18 g = 126 g ) of $H_2O$ to for the given formula

Therefore 1 g of $Mg SO_4$ x g of $H_2O$

So

$x = \frac{x]126 * 1}{ 120.4 }$

=> $x = 1.0465 \ g$

From our calculation we obtained that

1 g of $Mg SO_4$ will remove $x = 1.0465 \ g$ of $H_2O$

Then

$200 *10^{-3} \ g$ of $Mg SO_4$ will remove z g of $x = 1.0465 \ g$ of $H_2O$

So

$z = 200 *10^{-3} * 1.0465$

=> $z = 200 *10^{-3} * 1.0465$

=> $z = 0.2093 \ g$ of $H_2O$

6 0

3 years ago