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gayaneshka [121]
3 years ago
11

I need this answer before 7 can anyone help me please!

Chemistry
2 answers:
Alekssandra [29.7K]3 years ago
6 0

Answer:

In asthma, cells are deprived of oxygen hence leading in incomplete respiration, and less energy.

In diabetes, there's not enough insulin

Explanation:

rewona [7]3 years ago
5 0
With asthma the cells can’t get enough oxygen in order to function while with diabetes the cells don’t have enough insulin to function
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How to balance Mg3n2+H20>>Mg(oh)2+Nh3?
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Mg₃N₂ + 6H₂O  =  3Mg(OH)₂ + 2NH₃
4 0
3 years ago
In a video game a flying cocunut moves
Delvig [45]

Answer:

In a video game, a flying coconut moves at a constant velocity of 20 meters/second. The coconut hits an obstacle and moves in the opposite direction with a constant velocity of 10 meters/second.

Explanation:

8 0
3 years ago
If the element is closer to the top of the table is it's ionization energy larger?
Ulleksa [173]

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21

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3 0
3 years ago
Acetylene gas (ethyne; HC = CH) burns in an oxyacetylene torch to produce carbon dioxide and water vapor. The heat of reaction f
Yanka [14]

The mass of CO2 produced by 26g of acetylene is 88g.

Given ,

In an oxyacetylene torch, acetylene gas (ethyne; HCCH) burns to produce carbon dioxide and water vapour.

The acetylene combustion reaction is given by,

H2O + HCCH + 5/2 O=O 2CO2

Heat of reaction for acetylene combustion = 1259kj/mol

CO2 has a molecular mass of 44g/mol.

2 moles of CO2 have a molecular mass of 88g.

On combustion, 1 mole of acetylene yields 2 moles of CO2.

Thus, 26g of acetylene produces 88g of CO2 when burned.

As a result, the mass of carbon dioxide produced by 26g of acetylene is 88g.

Learn more about acetylene here :

brainly.com/question/15346128

#SPJ4

6 0
2 years ago
what mass of carbon dioxide gas would be produced if 10g of calcium carbonate reacted with an excess of hydrochloric acid?
LuckyWell [14K]
Answer is: 4,4 grams <span>of carbon dioxide gas would be produced.
</span>Chemical reaction: CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O.
m(CaCO₃) = 10 g.
n(CaCO₃) = 10 g ÷ 100 g/mol.
n(CaCO₃) = 0,1 mol.
From chemical reaction: n(CaCO₃) : n(CO₂) = 1 : 1.
n(CO₂) = 0,1 mol.
m(CO₂) = n(CO₂) · M(CO₂).
m(CO₂) = 0,1 mol· 44 g/mol.
m(CO₂) = 4,4 g.
7 0
4 years ago
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