Pv=nRT
where,p=199, R(constant)=8.314, V=4.67 T=30C=293K
n=pv/RT=0.38 moles
Answer: The limiting reactants for the reaction is, Mg
Explanation : Given,
Mass of = 10.1 g
Mass of = 10.5 g
Molar mass of = 24 g/mol
Molar mass of = 32 g/mol
First we have to calculate the moles of and .
and,
Now we have to calculate the limiting and excess reagent.
The balanced chemical equation is:
From the balanced reaction we conclude that
As, 2 mole of react with 1 mole of
So, 0.421 moles of react with moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Hence, the limiting reactants for the reaction is, Mg
The model that should show the corresct representation of xenon gas is one in which the gas molecules are isolated and monoatomic.
<h3>What is a noble gas?</h3>
A noble gas is a member of group 18 of the periodic table. Noble gases are known not to interact with each other and occur as monoatomic particles.
The images are not shown here hence the question is incomplete. However, we do know that any of the models that show individual monoatomic particles is a representation of xenon gas.
Learn more about noble gas: brainly.com/question/2094768
Answer:
This might be Option 2(b)
Explanation:
Answer:
4.52×10^24
Explanation:
N = n × Na
where; N = no. of bananas
n = no. of moles
Na = Avogadro's constant
Which is 6.02×10^23
N = 7.5 × 6.02×10^23
N =4.515×10^24