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iren2701 [21]
2 years ago
9

4.5cm wide by 5.750cm long by 1.50cm tall what is the volume of the box

Chemistry
1 answer:
Anni [7]2 years ago
5 0

Answer:

volume of box is 38.81 cm³.

Explanation:

Given data:

Width of box = 4.5 cm

Height of box = 5.750 cm

Length of box = 1.50 cm

Solution:

Formula:

Volume = length × height × width

by putting values,

V = 1.50 cm × 5.750 cm× 4.5 cm

V = 38.81 cm³

Thus, the volume of box is 38.81 cm³.

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Usimov [2.4K]

Answer:

nuclear is explosive and has potential energy while the other has kinetic energy

Explanation:

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3 years ago
In the following list, only is not an example of a chemical reaction
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(5points) Na2[Fe(OH2)2(OH)I3]absorbs photons with energy of 191kJ/mol. Calculate the wavelength (in nm) for a photon absorbed by
AfilCa [17]

Answer:

626.7nm

Explanation:

The energy of a photon is defined as:

E = hc / λ

<em>Where E is the energy of the photon, h is Planck constant (6.626x10⁻³⁴Js), c is speed of light (3x10⁸m/s) and </em>λ is the wavelength of light

The energy of 1 photon is:

(191000 J / mol) ₓ (1 mole / 6.022x10²³) = 3.1717x10⁻¹⁹ J

Replacing:

3.1717x10⁻¹⁹ J = <em>6.626x10⁻³⁴Jsₓ3x10⁸m/s /  </em>λ

λ = 6.267x10⁻⁷m

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<h3>626.7nm</h3>
6 0
3 years ago
8. Estimate the maximum volume percent of Methanol vapor that can exist at standard conditions. Vapor pressure = 88.5 mm Hg in a
sashaice [31]

Explanation:

Vapor pressure is defined as the pressure exerted by vapors or gas on the surface of a liquid.

It is known that at standard condition, vapor pressure is 760 mm Hg.

And, it is given that methanol vapor pressure in air is 88.5 mm Hg.

Hence, calculate the volume percentage as follows.

                  Volume percentage = \frac{\text{given vapor pressure}}{\text{standard vapor pressure}} \times 100

                                                    = \frac{88.5}{760} \times 100

                                                    = 11.65%

Thus, we can conclude that the maximum volume percent of Methanol vapor that can exist at standard conditions is 11.65%.

6 0
3 years ago
How is an oxidation half-reaction written using the reduction potential chart? How is the oxidation potential voltage determined
insens350 [35]
Oxidation  half  reaction  is  written   as    follows when  using  using  reduction potential  chart
example  when  using  copper  it is  written  as  follows
CU2+   +2e-  --> c(s)  +0.34v
 oxidasation  is the  loos  of  electron  hence copper oxidation  potential  is  as  follows
cu (s)  -->  CU2+   +2e    -0.34v

7 0
3 years ago
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