Answer:
D number of protons or atomic mass
Answer:
<h3>The answer is 7.47 g/cm³</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 53.137 g
volume = 7.11 cm³
We have
We have the final answer as
<h3>7.47 g/cm³</h3>
Hope this helps you
We can use the ideal gas equation to determine the temperature with the given conditions of mass of the gas, volume, and pressure. The equation is expressed
PV=nRT where n is the number of moles equal to mass / molar mass of gas. Substituting the given conditions with R = 0.0521 L atm/mol K we can find the temperature
Answer:
IR provides structural information about a molecule. TLC and melting point analysis do not provide structural information.
Explanation:
IR gives information about the functional groups present in a molecule. The vibrational frequency of each functional group gives information about the structure of the entire molecule.
Structural features of a molecule are deduced by matching the vibrational frequencies of groups obtained from the IR spectroscopy with that of known functional groups in literature.
Melting point is a qualitative method that can only yield information about the identity of a compound and not its structure. Each compound has its unique melting point recorded in literature and any pure sample of the same compound must have the same sharp meting point.
Thin-layer chromatography (TLC) is a chromatography technique used to separate non-volatile mixtures. After separating the components of the mixture, it does not give any information regarding the identity or the structure of the components of the mixture.
Therefore, only IR yields structural information about a sample.
Answer:
Mass = 5.92 g
Explanation:
Given data:
Volume of O₂ = 4.15 mol
Temperature and pressure = standard
Mass in gram = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
By putting values,
1 atm × 4.15L = n ×0.0821 atm.L /mol.K × 273.15 k
4.15 atm.L = n ×22.43 atm.L /mol
n = 4.15 atm.L / 22.43 atm.L /mol
n = 0.185 mol
Mass in gram:
Mas = number of moles × molar mass
Mass = 0.185 mol ×32g/mol
Mass = 5.92 g
