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emmasim [6.3K]
2 years ago
13

Se dea caer una pelota de basquetbol desde una altura de 90 metros.Calcular: El tiempo en que demorara en caer y a velcidad con

la que llega al suelo
Physics
1 answer:
GarryVolchara [31]2 years ago
5 0

Answer:

1. t = 4.24 s

2. v_{f} = 42.43 m/s

Explanation:

Podemos encontrar el tiempo de caída con la siguiente ecuación:

v_{f} = v_{0} + gt   (1)

En donde:

v_{f}: es la velocidad final de la pelota  

v_{0}: es la velocidad inicial = 0 (se deja caer)

g: es la aceleración debida a la gravedad = 10 m/s²

Debemos hallar primero la velocidad final. Podemos usar la ecuación:

v_{f}^{2} = v_{0}^{2} + 2gh  (2)

En donde:

h: es la altura = 90 m

v_{f} = \sqrt{2gh} = \sqrt{2*10 m/s^{2}*90 m} = 42.43 m/s

Entonces, la velocidad con la que la pelota llega al suelo es 42.43 m/s.

Ahora podemos encontar el tiempo que tarda en caer la pelota resolviendo la ecuación (1) para "t":

t = \frac{v_{f}}{g} = \frac{42.43 m/s}{10 m/s^{2}} = 4.24 s

Por lo tanto, la pelota tarda 4.24 segundos en caer.

Espero que te sea de utilidad!

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