Answer:
x = -8
Step-by-step explanation:
solve:
-4(2x+3) =2x+6-(8x+2)
-8x-12 = 2x+6-8x-2
-8x-12 = -6x + 4
-2x = 16
x = -8
Hope this helps.
Good Luck
Answer:
5 tokens
Step-by-step explanation:
<u><em>She spent 1 out of every 4 tokens,</em></u> meaning there are a couple of sets of 4 that we don't know many they are yet that she kept taking from every set 1 token, so if we do,
(Her total tokens) 20 ÷ 4 = 5.
This means that there's 5 sets, then we take 1 from every set so 1 × 5 = 5, that's it
I don't know if that was quite clear tho you can imagine it in a more virtual than mathematical way if you like,
Now Imagine you have 20 tokens in your hand, and you divide them into 5 sets, each set is a set of 4, you keep 3 in your hand then put 1 on a table, then you do this 5 times you'll end up with 5 tokens on the table and 15 in your hand.
<em>You can try that yourself if you want it to be more clear.</em>
Take 20 small pieces of paper, sticky notes or coins whatever you like, then divide them into sets of 4, then lastly take only 1 from each set (and by the way you'll notice that dividing each set into a set of 4 will make you automatically end up with 5 sets) now count all the 1's you collected from each set
they should be 5.
Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
