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vovikov84 [41]
2 years ago
9

Calculate the kilojoules needed to heat 231 g of gold from 18 ∘C to 195 ∘C.

Chemistry
1 answer:
LuckyWell [14K]2 years ago
8 0

5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.

We have 231 g of gold at 18 °C and supply it with heat to increase its temperature to 195 °C. We can calculate the amount of heat required using the following expression.

Q = c \times m \times \Delta T

where,

  • Q: heat
  • <em>c: specific heat capacity of gold</em> (0.129 J/g.°C)
  • m: mass
  • ΔT: change in the temperature

Q = \frac{0.129 J}{g.\° C}  \times 231 g \times (195 \° C - 18 \° C) = 5.27 \times 10^{3} J = 5.27 kJ

5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.

You can learn more about heating here: brainly.com/question/1105305

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Answer:

pH = 2.69

Explanation:

The complete question is:<em> An analytical chemist is titrating 182.2 mL of a 1.200 M solution of nitrous acid (HNO2) with a solution of 0.8400 M KOH. The pKa of nitrous acid is 3.35. Calculate the pH of the acid solution after the chemist has added 46.44 mL of the KOH solution to it.</em>

<em />

The reaction of HNO₂ with KOH is:

HNO₂ + KOH → NO₂⁻ + H₂O + K⁺

Moles of HNO₂ and KOH that react are:

HNO₂ = 0.1822L × (1.200mol / L) = <em>0.21864 moles HNO₂</em>

KOH = 0.04644L × (0.8400mol / L) = <em>0.0390 moles KOH</em>

That means after the reaction, moles of HNO₂ and NO₂⁻ after the reaction are:

NO₂⁻ = 0.03900 moles KOH = moles NO₂⁻

HNO₂ = 0.21864 moles HNO₂ - 0.03900 moles = 0.17964 moles HNO₂

It is possible to find the pH of this buffer (<em>Mixture of a weak acid, HNO₂ with the conjugate base, NO₂⁻), </em>using H-H equation for this system:

pH = pKa + log₁₀ [NO₂⁻] / [HNO₂]

pH = 3.35 + log₁₀ [0.03900mol] / [0.17964mol]

<h3>pH = 2.69</h3>
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