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lina2011 [118]
2 years ago
10

Which of the following animals could detect sound at a frequency of 67,000 Hz?

Physics
2 answers:
tatyana61 [14]2 years ago
7 0
C. BAT <span>can detect sound at a frequency of 67,000 Hz.

</span>
An elephant's frequency range is 16-12,000 Hz.
A tree frog's frequency range is 50 - 4,000 Hz
<span>A dog's frequency range is 67 - 45,000.</span>
Andrews [41]2 years ago
6 0
B) Bat
Think about it...
Bats use echolocation, which is basically a super high frequency sound wave, barely audible to humans, to find their food. 67,000 Hz is super high frequency, relative to human hearing of course. Bats would NEED to detect high frequency sounds if they wanted to detect their very own "echos".
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A student pushes a 2.85 kg cart causing it to accelerate at a rate of 4.9 m/s squared .What amount of force must the student hav
uysha [10]
In order to find the force (F), you would have to use the formula for it:
F=ma
where m is mass and a is acceleration.
In the problem, the mass is 2.85kg and the acceleration is 4.9m/s^2.
Therefore,
F=2.85kg(4.9m/s^2)
F=13.965kg(m/s^2)
Since N=kg(m/s^2)
F=13.965N
And because the problem requires that we use only 2 significant figures,
F=13N
Therefore, the student must exert 13N of force.

7 0
3 years ago
Which is a major area of study in psychology?mentalism totalculturalism behaviorism actionism
diamong [38]
Before the first behaviorist (Watson), Psychology was a part of philosophy.

4 0
2 years ago
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A dog has a mass of 60kg and an acceleration of 2m/s/s. What is the force of the dog?
attashe74 [19]

Answer:

120 N

Explanation:

F=ma therefore 60kg times 2m/s^2 is 120 N

8 0
2 years ago
A contestants spin a wheel when it is their turn in a game show. One contestant gives the wheel an initial angular speed of 3.40
guajiro [1.7K]

Answer:

4.62 s

Explanation:

We are given that

Initial angular speed,\omega=3.4 rad/s

\theta=1\frac{1}{4} rev=\frac{5}{4}\times 2\pi=2.5\pi rad

\omega'=0

\omega'^2-\omega^2=2\alpha \theta

Substitute the values

0-(3.4)^2=2\times 2.5\pi \alpha

\alpha=\frac{-(3.4)^2}{2\times 2.5\pi}=-0.736 rad/s^2

\omega'=\omega+\alpha t

0=3.4-0.736 t

-0.736t=-3.4

t=\frac{-3.4}{-0.736}=4.62 s

Hence, the wheel takes 4.62 s to come to rest.

3 0
3 years ago
power of a crane is 25000 watt calculate the time required by it to lift a load of 6000 kg up tp the height of 20 m​
saul85 [17]
Solution:

We have,

Power [P] = 25000 Watt

Mass [m] = 6000 kg

Height [h] = 20 metres

Time [t] = ?

Now,

P = W/t = F x d/t = mxgx h/t

Or, 25000 = 6000 x 10 x 20/25000 [.......g = 10

m/s^2]

Or, t = 6000 x 10 x 20/25000

Or, t = 1200/25

Therefore, t = 48 second

Hence, the required time for the crane to lift the load is 48 seconds.
8 0
3 years ago
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