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lina2011 [118]
3 years ago
10

Which of the following animals could detect sound at a frequency of 67,000 Hz?

Physics
2 answers:
tatyana61 [14]3 years ago
7 0
C. BAT <span>can detect sound at a frequency of 67,000 Hz.

</span>
An elephant's frequency range is 16-12,000 Hz.
A tree frog's frequency range is 50 - 4,000 Hz
<span>A dog's frequency range is 67 - 45,000.</span>
Andrews [41]3 years ago
6 0
B) Bat
Think about it...
Bats use echolocation, which is basically a super high frequency sound wave, barely audible to humans, to find their food. 67,000 Hz is super high frequency, relative to human hearing of course. Bats would NEED to detect high frequency sounds if they wanted to detect their very own "echos".
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Alexandra drops an egg from 30 m above the ground to hit Vanessa on the head. If Vanessa stands 3.5 meters tall. How fast is the
I am Lyosha [343]

This is problem of free falling objects, which can be solved using the formula:

V = sqrt(2gy)

Where v is the velocity upon impact

G is the acceleration due to gravity ( 9.81 m/s2)

Y is the height

Since Venessa is 3.5 m

Y = 30 -3.5 = 26.5 m

V = sqrt(2 (9.81 m/s2) ( 26.5 m))

<span>V = 22.8 m/s</span>

7 0
3 years ago
7) List three (3) automobile safety features currently used to minimize the risk of injury to its passengers. Relate these
r-ruslan [8.4K]
Seatbelt- strapped in egg
air bag- cushion around the egg
brakes- parachute(bag that helps the egg go down slower)
3 0
3 years ago
10. What is momentum of the water bottle before the collision? (read the
Alona [7]

Answer:

O ksm/s

Explanation:

before collision,

Velocity =0

So,momentum of the bottle before collision=mass ×velocity

=mass×0

=0 kgm/s

8 0
3 years ago
An unstrained horizontal spring has a length of 0.26 m and a spring constant of 180 N/m. Two small charged objects are attached
MakcuM [25]

Answer:

a)

two like charges always repel each other while two unlike charges attract each other. Since the spring stretches by 0.039 m, the charges have the same sign. both charges are positive(+) or Negative (-)

b)

both q1 and q1 are 8.35 × 10⁻⁶ C or -8.35 × 10⁻⁶ C

Explanation:

Given that;

L = 0.26 m

k = 180 N/m

x = 0.039 m

a)

we know that two like charges always repel each other while two unlike charges attract each other. Since the spring stretches by 0.039 m, the charges have the same sign.

b)

Spring force F = kx

F = 180 × 0.039

F = 7.02 N

Now, Electrostatic force F = Keq²/r²

where r = L + x = ( 0.26 + 0.039 )

we know that proportionality constant in electrostatics equations Ke = 9×10⁹ kg⋅m3⋅s−2⋅C−2

so from the equation; F = Keq²/r²

Fr² = Keq²

q = √ ( Fr² / Ke )

we substitute

q = √ ( 7.02 N × ( 0.26 + 0.039 )² / 9×10⁹ )

q = √ ( 7.02 N × ( 0.26 + 0.039 )² / 9×10⁹ )

q =  √ (0.627595 / 9×10⁹)

q = √(6.97 × 10⁻¹¹)

q = 8.35 × 10⁻⁶ C

Therefore both q1 and q1 are 8.35 × 10⁻⁶ C or -8.35 × 10⁻⁶ C

5 0
3 years ago
A car moves around a circular track at a constant rate. What must change?
suter [353]

B. only its velocity should change

4 0
3 years ago
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