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lina2011 [118]
3 years ago
10

Which of the following animals could detect sound at a frequency of 67,000 Hz?

Physics
2 answers:
tatyana61 [14]3 years ago
7 0
C. BAT <span>can detect sound at a frequency of 67,000 Hz.

</span>
An elephant's frequency range is 16-12,000 Hz.
A tree frog's frequency range is 50 - 4,000 Hz
<span>A dog's frequency range is 67 - 45,000.</span>
Andrews [41]3 years ago
6 0
B) Bat
Think about it...
Bats use echolocation, which is basically a super high frequency sound wave, barely audible to humans, to find their food. 67,000 Hz is super high frequency, relative to human hearing of course. Bats would NEED to detect high frequency sounds if they wanted to detect their very own "echos".
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The use of a beat or a rhythm to remember something is
Mamont248 [21]
<span>The answer is Music Mnemonics. Mnemonic is originally coming from the Ancient Greek word means “memory”. It is the study and development of systems for improving and assisting the memory. Mnemonic techniques are more specific memory aids. Music Mnemonic is a way we used to remember song lyrics and rhythmic movement.</span>
5 0
3 years ago
Read 2 more answers
Two manned satellites approaching one another at a relative speed of 0.550 m/s intend to dock. The first has a mass of 2.50 ✕ 10
NNADVOKAT [17]

Answer: Their final relative velocity is -0.412 m/s.

Explanation:

According to the law of conservation,

      m_{1}v_{1} + m_{2}v_{2} = (m_{1} + m_{2})v

Putting the given values into the above formula as follows.

      m_{1}v_{1} + m_{2}v_{2} = (m_{1} + m_{2})v

     2.50 \times 10^{3} kg \times 0 m/s + 7.50 \times 10^{3} kg \times -0.550 m/s = (2.50 \times 10^{3} kg + 7.50 \times 10^{3} kg)v

           -4.12 \times 10^{3} kg m/s = (10^{4} kg) v

                   v = \frac{-4.12 \times 10^{3} kg m/s}{10^{4} kg}

                      = -0.412 m/s

Thus, we can conclude that their final relative velocity is -0.412 m/s.

8 0
3 years ago
The bleeder is opened at a caliper and no brake fluid flows out. Technician A says that this is normal and that brake fluid shou
horsena [70]

Answer: b) Technician B only

Explanation:

For the fact no break fluid flows out Of the bleeder valve when It’s opened, that means there’s a blockage stopping the fluid from flowing off.

5 0
3 years ago
The same ball is shot straight up a second time from the same gun, but this time the spring is compressed only half as far befor
Mekhanik [1.2K]

Answer:

The new height the ball will reach = (1/4) of the initial height it reached.

Explanation:

The energy stored in any spring material is given as (1/2)kx²

This energy is converted to potential energy, mgH, of the ball at its maximum height.

If the initial height reached is H

And the initial compression of the spring = x

So, mgH = (1/2)kx²

H = kx²/2mg

The new compression, x₁ = x/2

New energy of loaded spring = (1/2)kx₁²

And the new potential energy = mgH₁

mgH₁ = (1/2)kx₁²

But x₁ = x/2

mgH₁ = (1/2)k(x/2)² = kx²/8

H₁ = kx²/8mg = H/4 (provided all the other parameters stay constant)

6 0
3 years ago
If one light bulb burns out in a string of lights, and the rest stay lit, it is reasonable to assume that the lights are wired i
Blizzard [7]
The lights are wired in PARALLEL.

In fact, when the lights are connected in parallel, they are connected on separate branches to the source of voltage, so if one light bulb burns out, the other lights continue to work because the current continues to flow in the other branches of the circuit.

Vice-versa, if the light bulbs are connected in series, they are on the same branch This means that if one of them burns out, the circuit is open in that point, so the current cannot flow anymore and the other light bulbs turn off as well.
4 0
2 years ago
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