If 16 mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced?
2 answers:
Answer:
32 mol
Explanation:
The balanced reaction from Oxygen and Hydrogen to form Water is:
(1/2)O₂ + H₂ ⇒ H₂O
So, 1/2 mol of oxygen forms 1 mol of water. The stoichiometry calculus must be:
1/2 mol of O₂ -------------------------- 1 mol of H₂O
16 mol of O₂ --------------------------- x mol of H₂O
By a direct simple three rule:
(1/2)x = 16
x = 32 mol
Answer:
32 mols of water
Explanation:
2H2 + O2 ==> 2H2O
What your givens are telling you and what the equation is saying is that
for every mol of O2, you get 2 mols of H2O
So you could do it with the proportion about.
1/16 = 2/x Cross multiply
x = 16 * 2
x = 32
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