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AlekseyPX
3 years ago
15

If 16 mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced?

Chemistry
2 answers:
Ket [755]3 years ago
8 0

Answer:

32 mol

Explanation:

The balanced reaction from Oxygen and Hydrogen to form Water is:

(1/2)O₂ + H₂ ⇒ H₂O

So, 1/2 mol of oxygen forms 1 mol of water. The stoichiometry calculus must be:

1/2 mol of O₂ -------------------------- 1 mol of H₂O

16 mol of O₂ --------------------------- x mol of H₂O

By a direct simple three rule:

(1/2)x = 16

x = 32 mol

Lynna [10]3 years ago
3 0

Answer:

32 mols of water

Explanation:

2H2 + O2 ==> 2H2O

What your givens are telling you and what the equation is saying is that

for every mol of O2, you get 2 mols of H2O

So you could do it with the proportion about.

1/16 = 2/x                 Cross multiply

x = 16 * 2

x = 32

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When silver nitrate reacts with copper, copper(II) nitrate and silver are produced. The balanced equation for this reaction is:
posledela

The question is incomplete, here is the complete question:

When silver nitrate reacts with copper, copper(II) nitrate and silver are produced. The balanced equation for this reaction is:

2AgNO_3+Cu\rightarrow Cu(NO_3)_2+2Ag

Suppose 6 moles of silver nitrate react. The reaction consumes___ moles of copper. The reaction produces __ moles of copper(II) nitrate and __ moles of silver.

<u>Answer:</u> The amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.

<u>Explanation:</u>

We are given:

Moles of silver nitrate = 6 moles

For the given chemical reaction:

2AgNO_3+Cu\rightarrow Cu(NO_3)_2+2Ag

  • <u>For copper metal:</u>

By Stoichiometry of the reaction:

2 moles of silver nitrate reacts with 1 mole of copper metal

So, 6 moles of silver nitrate will react with = \frac{1}{2}\times 6=3mol of copper metal

Moles of copper reacted = 3 moles

  • <u>For copper(II) nitrate:</u>

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 1 mole of copper(II) nitrate

So, 6 moles of silver nitrate will produce = \frac{1}{2}\times 6=3mol of copper(II) nitrate

Moles of copper(II) nitrate produced = 3 moles

  • <u>For silver metal:</u>

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 2 moles of silver metal

So, 6 moles of silver nitrate will produce = \frac{2}{2}\times 6=6mol of silver metal

Moles of silver metal produced = 3 moles

Hence, the amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.

6 0
3 years ago
Which of the following elements is a transition metal?
GenaCL600 [577]

Answer:

Scandium

Titanium

Vanadium

Chromium

Manganese

Iron

Cobalt

Nickel

Copper

Zinc

Yttrium

Zirconium

Niobium

Molybdenum

Technetium

Ruthenium

Rhodium

Palladium

Silver

Cadmium

Lanthanum

Hafnium

Tantalum

Tungsten

Rhenium

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Mercury

Actinium

Rutherfordium

Dubnium

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Hassium

Meitnerium

Darmstadtium

Roentgenium

Copernicium

Explanation:

all of those are transition metals lol

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