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VladimirAG [237]
3 years ago
6

Capsaicin, the compound that gives the hot taste to chili peppers, has the formula C18H27NO3. Its molar mass is 305.42 g/mol. Ca

lculate the mass percent of each element in the compound.
Chemistry
2 answers:
stellarik [79]3 years ago
5 0
Molar mass = 305.42 g/mol

C = ( 12 x 18 / 305.42 ) x 100 => 70.72 % of C

H = ( 1 x 27 / 305.42 ) x 100 => 8.84 % of H

N = ( 14 x 1 / 305.42 ) x 100 => 4.58 % of N

O = ( 16 x 3 / 305.42) x 100 => 15.71% of O

hope this helps!
ale4655 [162]3 years ago
4 0

Answer:

Explanation:  C_{18}H_{27}NO_{3}  is an organic compound with a nitro group present in it.

Given that the molar mass of the compound is 305.42 g/mol.

Mass percent of element is calculated by the mass of element divided by the total mass of the substance multiplied by 100.

Mass percent of carbon = (12 x 18) / 305.42 x 100 = 216/ 305.42 x 100 = 70.72%

Mass Percent of Hydrogen = (1 x 27) / 305.42 x 100 = 27/ 305.42 x 100 = 8.84%

Mass Percent of Nitrogen = (1 x 14)/ 305.42 x 100 = 14/ 305.42 x 100 = 4.58%

Mass Percent of Oxygen = (3 x 16)/ 305.42 x 100 = 48/ 305.42 x 100 = 15.71%

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Part IV. Limiting Reactants! A Challenge Problem!
Alexxandr [17]

Answer:

a. Fe2O3(s) + 2Al(s) → 2Fe(s) + Al2O3(s)

b. Fe2O3 is the limiting reactant.

c. 6.30 grams Fe

d. 52.6 %

Explanation:

Step 1: Data given

Mass of iron(III) oxide Fe2O3 = 9.00 grams

Mass of aluminium = 4.00 grams

Molar mass Fe2O3 = 159.69 g/mol

Aluminium molar mass = 26.98 g/mol

Step 2: The balanced equation

Fe2O3(s) + 2Al(s) → 2Fe(s) + Al2O3(s)

Step 3; Calculate Moles

Moles = mass / molar mass

Moles Fe2O3 = 9.00 grams / 159.69 g/mol

Moles Fe2O3 = 0.0564 moles

Moles Al = 4.00 grams / 26.98 g/mol

Moles Al = 0.148 moles

Step 4: Calculate limiting reactant

For 1 mol Fe2O3 we need 2 moles Al to produce 2 moles Fe and 1 mol Al2O3

Fe2O3 is the limiting reactant. It will completely be consumed (0.0564 moles).  Al is in excess. There will react 0.0564*2 = 0.1128 moles

There will remain 0.148 - 0.1128 = 0.0352 moles Al

Step 5: Calculate moles Fe

For 1 mol Fe2O3 we need 2 moles Al to produce 2 moles Fe and 1 mol Al2O3

For 0.0564 moles Fe2O3 we'll have 2*0.0564 = 0.1128 moles Fe

Step 6: Mass of Fe

Mass Fe = 0.1128 moles * 55.845 g/mol

Mass Fe = 6.30 grams

Step 7: If you carried out this reaction and it actually produced 0.475 mL of molten iron (r = 6.98 g/mL), what is the percent yield of this reaction?

Density = mass / volume

Mass = density * volume

Mass = 6.98 g/mL * 0.475 mL

Mass = 3.3155 grams

Percent yield = (actual mass / theoretical mass) * 100%

Percent yield = (3.3155 /6.30 ) * 100 %

Percent yield = 52.6 %

3 0
2 years ago
Megan prepares a pitcher of lemonade by adding a quarter cup of granular sugar to the mixture. Which action should she take so t
Licemer1 [7]
Can someone please help me with my chem review
3 0
3 years ago
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H2SO4 + 2 KOH --> K2SO4 + 2 H2O
alisha [4.7K]
Double replacement because H and K are both switching
8 0
3 years ago
How many grams are 3.01 × 1023 molecules of CuSO4?
zvonat [6]
Answer is: 79.8 grams of copper(II) sulfate.
N(CuSO₄) = 3.01·10²³; number of molecules.
n(CuSO₄) = N(CuSO₄) ÷ Na.
n(CuSO₄) = 3.01·10²³ ÷ 6.02·10²³ 1/mol.
n(CuSO₄) = 0.5 mol; amount of substance.
m(CuSO₄) = n(CuSO₄) · M(CuSO₄).
m(CuSO₄) = 0.5 mol · 159.6 g/mol.
m(CuSO₄) = 79.8 g; mass of substance.
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4 0
3 years ago
What is an atomic radius?
Vikki [24]

Explanation:

The atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons

8 0
2 years ago
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