Answer:
[Co(H₂O)₆]²⁺ = 0.361 M
Explanation:
[CoCl₂ . 6H₂O] + 2Cl⁻ → [CoCl₄]²⁻ + 6H₂O
[Co(H₂O)₆]²⁺ + 4Cl⁻ → [CoCl₄]²⁻ + 6H₂O
[CoCl₄]²⁻ = 0.361 M ∴ [Co(H₂O)₆]²⁺ = 0.361 M
The equation shows that the concentration of [Co(H₂O)₆]²⁺ should be equal to the concentration of [CoCl₄]²⁻.
Answer:
11
Explanation:
Data obtained from the question include:
Mass number = 23
Neutron = 12
Atomic number =.?
Next, we shall determine the number of protons present in the element.
This can be achieved by doing the following:
Mass number = Proton + Neutron
Mass number = 23
Neutron = 12
Proton =...?
Mass number = Proton + Neutron
23 = Proton + 12
Collect like terms
Proton = 23 – 12
Proton = 11
The atomic number of an element is equal to the proton number.
Atomic number = proton number
Proton number = 11
Atomic number = proton = 11
Therefore, the atomic number is 11.
The oxidation number of a pure element is zero.
We write the following substances' chemical formula as follows:
Ferric hydrogen sulphate = Fe(HSO4)3.<span>
Tungsten (V) peroxide = </span>W2(O2)5<span>
Nitric acid = HNO3
Aluminum acetate = </span>C6H9AlO6
Hope this answers the question. Have a nice day.
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The ratio of densities, d₀₃/d₀ is 3:2
We know that at STP all gas have the same volume that is 
.
Dioxygen 
Ozone 1 mole 
.
The ratio of densities,
do3: do2 = 3:2
Oxygen is found naturally as a molecule. two oxygen atoms strongly bind together with a covalent double bond to shape dioxygen or O2. Oxygen is normally observed as a molecule. it is referred to as dioxygen.
After hydrogen and helium, oxygen is the third most plentiful element in the universe and the most established element in the world. two atoms of the factors combine to generate dioxygen, an odourless and colourless diatomic gasoline with the formulation O2, at ordinary temperature and stress.
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