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Studentka2010 [4]
2 years ago
11

The exploration of the mid-cayman rise is intended to discover _______. a. what life may have been like before the evolution of

photosynthesis b. the origins of photosynthesis c. life in shallow, coastal regions d. the chemical composition of undersea mountains
Chemistry
1 answer:
Soloha48 [4]2 years ago
4 0

The exploration of the mid-cayman rise is intended to discover that what life may have been like before the evolution of photosynthesis.

<h3>What is mid - cayman rise?</h3>

Mid - cayman rise is an area or era where only some amount of light is coming but still existence of life is present there.

As we know that plants make their own food by the process called photosynthesis in the presence of light, but this is not the scenario for all the time. Before the discovery of photosynthesis plants also prepared their own food.

Hence, option (a) is correct.

To know more about photosynthesis, visit the below link:

brainly.com/question/4341036

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The radius of the smaller circle is 8 feet. The distance from the rim of the inner circle to the rim of the outer circle is 3 fe
postnew [5]

Answer:

178.98 sq. feet

Explanation:

The path and the garden has been shown in the figure below. The green area is the garden and the area in brown is the path.

It has been given that,

Radius of garden = 8 feet

So, the area of garden = 3.14 × 8 × 8 = 200.96 sq. feet

The total radius of the land including garden and path = 8 + 3 = 11 feet

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5 0
4 years ago
what is the amount of heat,in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22c to 66c
aniked [119]

Answer :

the amount of heat,in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22°c to 66°c is 9.104 Joules.

Explanation:

The answer can be calculated using the formula

Q = mCрΔT

where

Q is the amount of heat required in joules to raise the temperature.

m is the mass of the sample in Kg.

Cp is the specific heat of the sample in J/Kg°C.

ΔT is the change in temperature required.

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Cp = 4.18 J/Kg°C (for water)

T₁ = 22°C  ; T₂ = 66°C

ΔT =  66 - 22 = 44

Substituting values in Q = mCрΔT

Q = (0.0495)(4.18)(44)

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5 0
3 years ago
Density is considered what type of property
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What is the density of a substance with a volume of 5.0 mL and a mass of 15.0g?
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Explanation:

density formula: mass/volume

15/5=3

8 0
3 years ago
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