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Studentka2010 [4]
2 years ago
11

The exploration of the mid-cayman rise is intended to discover _______. a. what life may have been like before the evolution of

photosynthesis b. the origins of photosynthesis c. life in shallow, coastal regions d. the chemical composition of undersea mountains
Chemistry
1 answer:
Soloha48 [4]2 years ago
4 0

The exploration of the mid-cayman rise is intended to discover that what life may have been like before the evolution of photosynthesis.

<h3>What is mid - cayman rise?</h3>

Mid - cayman rise is an area or era where only some amount of light is coming but still existence of life is present there.

As we know that plants make their own food by the process called photosynthesis in the presence of light, but this is not the scenario for all the time. Before the discovery of photosynthesis plants also prepared their own food.

Hence, option (a) is correct.

To know more about photosynthesis, visit the below link:

brainly.com/question/4341036

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the development and use of the ______ a common and important piece of laboratory equipment, led scientist to the discovery of se
Liula [17]

The answer is the Microscope.

6 0
3 years ago
How many grams of sulfur are needed to react completely with 246 g of mercury to form hgs?
iren [92.7K]

The reaction between mercury (Hg) and sulfur (S) to form HgS is:

Hg + S ------------- HgS

Therefore: 1 mole of Hg reacts with 1 mole of S to form 1 mole of HgS

The given mass of Hg = 246 g

Atomic mass of Hg = 200.59 g/mol

# moles of Hg = 246 g/ 200.59 gmol-1 = 1.226 moles

Based on the reaction stoichiometry,

# moles of S that would react = 1.226 moles

Atomic mass of S = 32 g/mol

Therefore, mass of S = 1.226 moles*32 g/mole = 39.23 g

39.2 g of sulfur would be needed to react completely with 246 g of Hg to produce HgS

5 0
3 years ago
Read 2 more answers
What is the charge of oxygen in Na2O?
Nuetrik [128]

In Na2O, what is the oxidation state of oxygen? In Na2O oxidation state of Na is 1+
3 0
3 years ago
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HELP PLEASE (Solve this problem using the appropriate law). what is the volume of 0.382 moles of hydrogen gas at 1.50 atmosphere
kaheart [24]

Answer:

V = 6.17 L

Explanation:

Given data:

Volume = ?

Number of moles = 0.382 mol

Pressure = 1.50 atm

Temperature = 295 k

R = 0.0821 L. atm. /mol. k

Solution:

According to ideal gas equation:

PV= nRT

V = nRT/P

V = 0.382 mol × 0.0821 L. atm. /mol. k ×295 k / 1.50 atm

V = 9.252  L. atm.  / 1.50 atm

V = 6.17 L

5 0
3 years ago
Determine the theoretical yield of HCl if 60.0 g of BC13 and 37.5 g of H20 are reacted according to the following balanced react
Pie

Answer : The theoretical yield of HCl is, 56.1735 grams

Explanation : Given,

Mass of BCl_3 = 60 g

Mass of H_2O = 37.5 g

Molar mass of BCl_3 = 117 g/mole

Molar mass of H_2O = 18 g/mole

Molar mass of HCl = 36.5 g/mole

First we have to calculate the moles of BCl_3 and H_2O.

\text{Moles of }BCl_3=\frac{\text{Mass of }BCl_3}{\text{Molar mass of }BCl_3}=\frac{60g}{117g/mole}=0.513moles

\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{37.5g}{18g/mole}=2.083moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

BCl_3(g)+3H_2O(l)\rightarrow H_3BO_3(s)+3HCl(g)

From the balanced reaction we conclude that

As, 1 mole of BCl_3 react with 3 mole of H_2O

So, 0.513 moles of BCl_3 react with 3\times 0.513=1.539 moles of H_2O

From this we conclude that, H_2O is an excess reagent because the given moles are greater than the required moles and BCl_3 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of HCl.

As, 1 mole of BCl_3 react to give 3 moles of HCl

So, 0.513 moles of BCl_3 react to give 3\times 0.513=1.539 moles of HCl

Now we have to calculate the mass of HCl.

\text{Mass of }HCl=\text{Moles of }HCl\times \text{Molar mass of }HCl

\text{Mass of }HCl=(1.539mole)\times (36.5g/mole)=56.1735g

Therefore, the theoretical yield of HCl is, 56.1735 grams

7 0
3 years ago
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