Answer: 0.0163
Explanation: fn=n x v/2L
Fundamental frequency =f1
1 x (343/2L) = 10500
Rearrange the equation
L= v/(2xFn)
L= 343/(2x10500)
L=0.0163
The formula that we will going to use in this question is simply P1V1/T1 = P2V2/T2 where T is the constant.
P1V1 = P2V2
P2 = P1V1/V2 = (V1 / V2) x P2 = (13.0 L / 6.5 L) x 0.76 atm = 1.5 atm
The answer in this question is 1.5 atm
To solve this problem we will apply the linear motion kinematic equations. To determine the position in which the braking starts we will start from the definition of distance as a function of speed and time, that is
Here,
= Initial position
v = Velocity
t = time
Replacing we have that
Now the acceleration is given by the function,
Here,
= Final velocity
= Initial velocity
a = Acceleration
x = Displacement
Replacing we have that
Therefore the acceleration necessary to bring the train to rest is 
Answer:
y=-3.2x+18.5 Hope This Helps Tell me if you need step by step
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