Answer:
since each loop is ewuvivalent to one half wave lenght . the length of the string is equal to two halves of a wavelength . put in the form of an equation in the same reasoning also
Answer:
Evaporative Water Loss = 2 kg
Explanation:
According to the given condition, the water entering the body must be equal to the water leaving the body. Therefore,
Water Entering the Body = Water Leaving the Body
Feed Water + Drinking Water + Metabolic Water = Urine Water + Evaporative Water Loss
using the given values:
1 kg + 5 kg + 0.5 kg = 4.5 kg + Evaporative Water Loss
Evaporative Water Loss = 1 kg + 5 kg + 0.5 kg - 4.5 kg
<u>Evaporative Water Loss = 2 kg</u>
Hello! The nontoxic, nonflammable chemicals containing atoms of carbon, chlorine, and fluorine that have created a hole in the ozone layer are the Chlorofluorocarbons (CFCs)
These are compounds developed and improved by Thomas Midgley in the late 1920s. They were used as refrigerants and aerosol propellants.
These compounds created a hole in the ozone layer by the following reactions:
CCl₃F → CCl₂F· + Cl· (In the presence of light. Radical Reaction)
Cl· + O₃ → ClO + O₂
ClO + O₃ → Cl· + O₂
The last 2 reactions can repeat in a radical mechanism and explain why these compounds are so harmful to the ozone layer.
Answer:
a) 
b) 
Explanation:
From the question we are told that:
Density 
Velocity of wind 
Dimension of rectangle:50 cm wide and 90 cm
Drag coefficient 
a)
Generally the equation for Force is mathematically given by



Therefore Torque



b)
Generally the equation for torque due to weight is mathematically given by

Where

Therefore




Answer: MR²
is the the moment of inertia of a hoop of radius R and mass M with respect to an axis perpendicular to the hoop and passing through its center
Explanation:
Since in the hoop , all mass elements are situated at the same distance from the centre , the following expression for the moment of inertia can be written as follows.
I = ∫ r² dm
= R²∫ dm
MR²
where M is total mass and R is radius of the hoop .