The rock would be at a point 12 m from water at a time <u>4.8 s</u>.
Take the origin of the coordinate system at the top of the cliff. It is thrown upwards with a velocity u. When the rock is at a point 12 m from water, calculate the vertical displacement of the rock from the origin.
Use the equation of motion,
The rock falls under the acceleration due to gravity, directed down wards.
Substitute 18 m/s for u, -26 m for y and -9.8 m/s² for a=g.
Solve the quadratic equation for t.
Taking only the positive value,
After a time of <u>4.8 s</u> the rock would be at a distance of 12 m from water.
Answer:
Average speed, v = 25 m/s
Explanation:
It is given that,
Distance travelled by the object, d = 50 meters
Time taken, t = 2 seconds
Average speed is defined as the total distance divided by total time taken i.e.
v = 25 m/s
So, the sped of the object is 25 m/s. Hence, this is the required solution.
Answer:
let current flow be x
Explanation:
than we know potential difference = energy supply / charge then 120 = 10 /x then x=12 therefore pd = 12 v
It’s red shift and blue shift because This only occurs when the frequency of the wave is made longer or shorter due to the movement of the source relative to the observer
Answer:
It tells us
Explanation:
The number of valence shell electrons in an element's atom that is measured by a vertical column in the periodic table.
