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3 years ago

How does weathering alter the surface of land? Is it D?

1 answer:

4 0

I don't think the shaping of the beach or hill would be considered
weathering, especially since it says "as smaller particles are moved
away". This one is just talking about where the particles decide to
gather and make a shape.

'C' is really talking about weathering, where rocks are broken up into
stones, and the stones into smaller pieces that can be blown away
on the wind. THAT's weathering.

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How do you answer this. Need help ASAP. Offering 20 points !!!

Temka [501]

in this since your volume remains at a constant you'll need to use Gay-Lussacs law, p1/t1=p2/t2.

your temp should be converted in kelvin

variables:

p1=3.0×10^6 n/m^2

t1= 270k

just add 273 to your celcius

p2= ? your solving for this

t2= 315k

then you set up the equation

(3.0×10^6)/270= (x)(315)

you then cross multiply

(3.0×10^6)315=270x

distribute the 315 to the pressure.

9.45×10^8=270x then you divide 270 o both sides to get

answer

3.5×10^6 n/m^2

7 0

3 years ago

An airplane is flying in a horizontal circle at a speed of 92.1 m/s. The 55.6 kg pilot does not want his radial acceleration to

Fudgin [204]

Answer:

r = 102.43 m

Explanation:

Newton's second law for this case is

F = ma

Where the acceleration is centripetal

a = v² / r

r = v² / a

They indicate that the radial acceleration is 8.45 g

r = v² / 8.45 g.

r = 92.1² / 8.45 9.8

r = 102.43 m

7 0

3 years ago

How much work is done by the force lifting a

Ann [662]

The work done in lifting the hamburger is equal to the increase in gravitational potential energy of the hamburger, given by

$W=\Delta U=mg \Delta h$

where

m=0.1 kg is the mass of the hamburger

$g=9.81 m/s^2$ is the gravitational acceleration

$\Delta h=0.3 m$ is the increase in height of the hamburger

Substituting numbers into the equation, we find

$W=(0.1 kg)(9.81 m/s^2)(0.3 m)=0.3 J$

So, the correct answer is

(3) 0.3 J

3 0

4 years ago

Why does a dropped feather hit the ground later than a rock dropped at the same time? *

MissTica

The air resistance on the feather would be the correct answer.

7 0

3 years ago

Read 2 more answers

A box is placed on a conveyor belt that moves with a constant speed of 1.05 m/s. The coefficient of kinetic friction between the

sveticcg [70]

Answer:

The box stops in 0.139 seconds, after moving 7.29cm (0.0729m) backwards relative to the belt.

Explanation:

As the box is initially at rest relative to the earth, it is moving backwards with a speed of 1.05m/s relative to the belt. Then, the frictional force acts on the box to make it stop relative to the belt. So, we first have to write the equations of motion of the box in each axis:

$x: f_k=ma\implies a=\frac{f_k}{m} \\\\y: N-mg=0\implies N=mg$

Since the frictional force $f_k$ is equal to $f_k=\mu_k N=\mu_k mg$ , then we have that the acceleration is:

$a=\frac{\mu_k mg}{m}=\mu_k g$

Now, from the definition of acceleration we get:

$a=\frac{v-v_0}{t}\implies t=\frac{v-v_0}{a}$

And, as the final velocity is zero because the box gets to a stop, we have:

$t=-\frac{v_0}{a}=-\frac{v_0}{\mu_k g}$

(Don't worry about the negative sign. It will disappear because the initial velocity is also negative, since we take the box initially moving backwards)

Then, plugging in the given values, we calculate the time:

$t=-\frac{(-1.05m/s)}{0.770(9.81m/s^{2})}=0.139s$

In words, the time the box takes to stop sliding relative to the belt is 0.139s.

The displacement of the box in this time, is given by the kinematics formula:

$v^{2}=v_0^{2}+2ax\implies x=-\frac{v_0^{2}}{2\mu_kg}$

Finally, we calculate the displacement:

$x=-\frac{(1.05m/s)^{2} }{2(0.770)(9.81m/s^2)}=-0.0729m=-7.29cm$

This means that the box moves 7.29cm backwards relative to the belt.

4 0

3 years ago