Answer:
average force = 385,140 N
Explanation:
from the question we are given the following
mass (m) = 1800 kg
distance of fall (d) = 3 m
driven distance (l) = 14.4 cm = 0.144 m
acceleration due to gravity (g) = 9.8 m/s^{2}
work done = average force x driven distance.....equation 1
and
work done = change in kinetic energy + change in potential energy
work done = (0.5 x m x (v^{2} - u^{2})) + (m x g x (-d-l))
- Initial velocity (u) and final velocity (v) are zero because the pile driver is it rest before it moves to hit the pile and after hitting the pile.
- The changes in length for the potential energy are negative because the pile moves downward
we now have work done = (m x g x (-d-l))...equation 2
now equating the two equations for work done we have
average force x driven distance = (m x g x (-d-l))
average force x 0.144 = 1800 x 9.8 x (-3-0.144)
average force = (1800 x 9.8 x (-3-0.144)) ÷ 0.144
average force = 385,140 N
Answer: A negatively charged particle that is found in atoms.
Your answer for question two is right
