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Whitepunk [10]
3 years ago
5

As a general rule of thumb, the greater the altitude of the top of a thunderstorm cloud (cumulonimbus), the more intense the thu

nderstorm cell. a relatively high thunderstorm top implies vigorous convection and a relatively ________ updraft.
Physics
1 answer:
olga_2 [115]3 years ago
3 0
A relatively strong updraft
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In 1998, scientists discovered that the expansion of the universe has been accelerating.
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Dang that’s a cool fact bro
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n this experiment, you will measure mass and volume of various sport balls, both regularly shaped ball and irregularly shaped. W
pentagon [3]

Explanation :

Density of an object can determine using mass and volume. We can measure mass and volume of various sports ball, both regular shaped ball and irregular shaped ball.

Density for regularly shaped ball and that of irregularly shaped ball is different.

Suppose that mass of an object is 100g and the volume is 2000\ cm^3 . So, using this data we can find density of that object as

density=\frac{mass}{volume}

\rho =\frac{100}{2000}

\rho =0.05\ g/cm^3

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Uri looks through a telescope for two stars. He knows that both stars have the same absolute brightness and that the second star
scZoUnD [109]

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b

Explanation:

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There is a current I flowing in a clockwise direction in a square loop of wire that is in the plane of the paper. If the magneti
MArishka [77]

Answer:

IBL²

Explanation:

Given that

Current flowing in the wire, is I

Magnetic field towards the right, is B

Length of each side of the loop, is L

Number of windings on the loop, is N

Torque exerted on the wire, is T

The torque, T is usually given by the formula

Torque, T = NBIAsinθ,

and if N = 1 and sinθ = 1 also, then we have

Torque, T = BIA

And we know that Area A from this particular question will be given as = L². If we then substitute A for L², we then have

Torque, T = IBL²

4 0
3 years ago
An electron is placed on a line connecting two fixed point charges of equal charge but the opposite sign. The distance between t
viktelen [127]

Answer:

a)    F_net = 6.48 10⁻¹⁸ ( \frac{1}{x^2} + \frac{1}{(0.300-x)^2} ),   b) x = 0.15 m

Explanation:

a) In this problem we use that the electric force is a vector, that charges of different signs attract and charges of the same sign repel.

The electric force is given by Coulomb's law

         F =k \frac{q_2q_2}{r^2}

         

Since when we have the two negative charges they repel each other and when we fear one negative and the other positive attract each other, the forces point towards the same side, which is why they must be added.

          F_net= ∑ F = F₁ + F₂

let's locate a reference system in the load that is on the left side, the distances are

left side - electron       r₁ = x

right side -electron     r₂ = d-x

let's call the charge of the electron (q) and the fixed charge that has equal magnitude Q

we substitute

          F_net = k q Q  ( \frac{1}{r_1^2}+ \frac{1}{r_2^2})

          F _net = kqQ  ( \frac{1}{x^2} + \frac{1}{(d-x)^2} )

         

let's substitute the values

          F_net = 9 10⁹  1.6 10⁻¹⁹ 4.50 10⁻⁹ ( \frac{1}{x^2} + \frac{1}{(0.30-x)^2} )

          F_net = 6.48 10⁻¹⁸ ( \frac{1}{x^2} + \frac{1}{(0.300-x)^2} )

now we can substitute the value of x from 0.05 m to 0.25 m, the easiest way to do this is in a spreadsheet, in the table the values ​​of the distance (x) and the net force are given

x (m)        F (N)

0.05        27.0 10-16

0.10          8.10 10-16

0.15          5.76 10-16

0.20         8.10 10-16

0.25        27.0 10-16

b) in the adjoint we can see a graph of the force against the distance, it can be seen that it has the shape of a parabola with a minimum close to x = 0.15 m

4 0
3 years ago
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