By working with percentages, we want to see how many inches is the center of gravity out of the limits. We will find that the CG is 1.45 inches out of limits.
<h3>What are the limits?</h3>
First, we need to find the limits.
We know that the MAC is 58 inches, and the limits are from 26% to 43% MAC.
So if 58 in is the 100%, the 26% and 43% of that are:
- 26% → (26%/100%)*58in = 0.26*58 in = 15.08 in
- 43% → (43%/100%)*58in = 0.43*58 in = 24.94 in.
But we know that the CG is found to be 45.5% MAC, then it measures:
(45.5%/100%)*58in = 0.455*58in = 26.39 in
We need to compare it with the largest limit, so we get:
26.39 in - 24.94 in = 1.45 in
This means that the CG is 1.45 inches out of limits.
If you want to learn more about percentages, you can read:
brainly.com/question/14345924
Ke= 1/2 x m x v^2
Ke= 1/2 x 2.1 x 30^2
Energy = 945 J
Answer:
9(3x-2y)
Explanation:
27x-18y, the common factor here is 9
9(3x-2y)
Answer:
Approximately 
(assuming that external forces on the cannon are negligible.)
Explanation:
If an object of mass 
is moving at a velocity of 
, the momentum 
of that object would be 
.
Momentum of the t-shirt:
.
If there is no external force (gravity, friction, etc.) on this cannon, the total momentum of this system should be conserved. In other words, if 
denote the momentum of this cannon:
.
.
Rewrite to obtain 
. Since the mass of this cannon is 
, the velocity of this cannon would be:
.
