Colurs of Phenolphthalein at different pH's are as follow,
When pH is less than zero, means when the conditions are strongly acidic then it imparts Orange Color.
At pH ranging from zero to 8.2 (acidic or weakly acidic conditions) it is colorless.
At pH ranging from 8.2 to 12 (Basic conditions) it imparts Pink color.
At pH greater than 13 (strongly basic) it is again Colorless.
Result:
So, At pH = 11 <span>phenolphthalein solution gives Pink Color.</span>
Proton and Neutron numbers within an atom cannot change, however, the electron number may change and form an ion. The answer is True
109.5 degrees should be the answer you are looking for :D
1) At tne same temperature and with the same volume, initially the chamber 1 has the dobule of moles of gas than the chamber 2, so the pressure in the chamber 1 ( call it p1) is the double of the pressure of chamber 2 (p2)
=> p1 = 2 p2
Which is easy to demonstrate using ideal gas equation:
p1 = nRT/V = 2.0 mol * RT / 1 liter
p2 = nRT/V = 1.0 mol * RT / 1 liter
=> p1 / p2 = 2.0 / 1.0 = 2 => p1 = 2 * p2
2) Assuming that when the valve is opened there is not change in temperature, there will be 1.00 + 2.00 moles of gas in a volumen of 2 liters.
So, the pressure in both chambers (which form one same vessel) is:
p = nRT/V = 3.0 mol * RT / 2liter
which compared to the initial pressure in chamber 1, p1, is:
p / p1 = (3/2) / 2 = 3/4 => p = (3/4)p1
So, the answer is that the pressure in the chamber 1 decreases to 3/4 its original pressure.
You can also see how the pressure in chamber 2 changes:
p / p2 = (3/2) / 1 = 3/2, which means that the pressure in the chamber 2 decreases to 3/2 of its original pressure.