Answer:
Relative abundance of each isotopes of an element.
Explanation:
Consider the following example:
Uranium is used in nuclear reactors and is a rare element on earth. Uranium has three common isotopes. If the abundance of 234U is 0.01% the abundance of 235U is 0.71% and the abundance of 238U is 99.28% what is the average atomic mass of uranium
Abundance of U²³⁴ = 0.01%
Abundance of U²³⁵ = 0.17%
Abundance of U²³⁸ = 99.28%
Average atomic mass = ?
Solution:
Average atomic mass of uranium = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) +(abundance of 3rd isotope × its atomic mass) / 100
Average atomic mass of uranium= (234×0.01)+(235×0.71)+(238×99.28)/100
Average atomic mass of uranium= 2.34 + 166.85 + 23628.64 / 100
Average atomic mass of uranium= 23797.83 / 100
Average atomic mass of uranium= 237.98 amu.
hard because it has calcium and magnesium
Answer:
Evaporation and Condensation... Hope this helps : )
Explanation:
Answer:
Heat, Q = 3035.073 J
Explanation:
It is given that,
Mass of water, m = 15.5 g
Initial temperature, 
Final temperature, 
The specific heat of water is, c = 4.184 J/ g°C
The heat removed or absorbed by water is given by formula as :
So, the heat of 3035.073 J is removed from 15.5 g of water.
Answer:
1. balance observation using "how much" = 5. quantitative instrument
2. graduated cylinder = 4. quantitaive instrument of volume
3. hypothesis proposed explanation= 7. qualitative descriptive observation
4. unit of volume= L
6. kg = primary unit of mass
Explanation:
there seem to be some typo error in uploading question but still it was clear to answer.
