The boiling point is the temperature at which the vapour pressure of the solution or solvent becuase equal to the ambient pressure, and bubbles of vapour from directly in the liquid. The normal boiling point is specified when the ambient pressure ( And also thvapour pressure of the boiling liquid) is One atmosphere. Ans so where strong intermolecular forces of attraction operate for instance in Hydrogen-Bonded liquids, boiling point should be elevated. More energy has to be put into the system to disrupt the intermolecular force. And the best indicator or intermolecular or inter-particle force is boiling point.
Answer:
is the correct answer to the given question.
Explanation:
Given k=6.40 x 10-3 min-1.
According to the first order reaction .
The concentration of time can be written as
![[\ A\ ]\ = \ [\ A_{0}\ ] * e \ ^\ {-kt}](https://tex.z-dn.net/?f=%5B%5C%20A%5C%20%5D%5C%20%3D%20%5C%20%5B%5C%20%20A_%7B0%7D%5C%20%5D%20%20%2A%20e%20%5C%20%5E%5C%20%20%7B-kt%7D)
Here ![[\ A\ ]_{0}](https://tex.z-dn.net/?f=%5B%5C%20A%5C%20%5D_%7B0%7D)
= Initial concentration.
So ![[\ A\ ]_{0}= 0.0314 M](https://tex.z-dn.net/?f=%5B%5C%20A%5C%20%5D_%7B0%7D%3D%200.0314%20M)
Putting this value into the above equation.
=0.211 M
This can be written as
The balanced chemical reaction is
NaCl + AgNO3 --> AgCl + NaNO3
To find out if precipitation will occur, we need to calculate the number of
moles acting in the chemical reaction
But Molarity, M=nV, where n is the number of moles and V is the volume in
litres. So n = M/V
number of moles of AgNo3 = 0.02/500 * 10^(-3)
n= 0.04
While n of Sodium chloride = 0.01/0.5 = 0.2. Since there is excess sodium chloride ( twice as much) precipitation will not occur. 2NaCl + 2AgNO3 -->
2AgCl + 2NaNO3. The reaction requires one and not two moles of AgNo3 as evident from the number of moles which is 0.04
The Indicator changes color in a titration is Indicator Point
To form a 2+ ion, you need to lose two negatively charged electrons. Because metals have relatively empty outer shells, they lose electrons. Metals are on the left hand side of the table, and in order to lose two electrons, you need to have two electrons to start with. The groups of the table are based on the number of electrons an element has in the outer shell, so Group 2 metals will lose two electrons to gain a 2+ charge
