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pickupchik [31]

2 years ago

13

If water turns deep red with a few drops of potassium thiocyanate, what cation is likely present?.

1 answer:

babunello [35]2 years ago

3 0

Answer:

Fe3^+

$fe3 ^{ + }$

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How many moles of Oxygen is produced when you begin with 7.16 moles of KCl?

ohaa [14]

According to the balanced reaction equation:

2KClO3→ 2KCl + 3O2

from this equation, we can see that the molar ratio between KCl & O2 is 2 : 3

so, 2 moles of KCl will need 3 moles of O2

∴ 7.16 moles of KCl will need X moles of O2

∴number of moles of O produced = 7.16 * 3 / 2

= 10.74 moles

8 0

3 years ago

What is the formula for the compound formed by a magnesium cation (Mg2+) and a fluoride anion (F- )?

Tanya [424]

Answer:

MgF₂

Explanation:

Fluorine only has a 1- charge, so to satisfy the 2+ charge on magnesium–– you need 2 fluorine atoms to balance out the charges.

6 0

3 years ago

What is the pH of a solution with [OH-] = 5.40 x 10-3 M?

igomit [66]

pH: 5.4E-3
pOH: 13.9946
[H+]: 0.987643022777
[OH-]: 1.01251158256E-14 acid

7 0

3 years ago

What is the electromagnetic spectrum?

Ganezh [65]

Answer:

the range of wavelengths or frequencies over which electromagnetic radiation extends.

Explanation:

5 0

3 years ago

What is the pH of a solution prepared by mixing 30.00 mL of 0.10 MCH3CO2H with 30.00 mL of 0.030 MCH3CO2K? Assume that the volum

zysi [14]

Answer : The pH of the solution is, 4.2

Explanation : Given,

$K_a=1.8\times 10^{-5}$

Concentration of $CH_3CO_2H$ = 0.10 M

Concentration of $CH_3CO_2K$ = 0.030 M

First we have to calculate the value of $pK_a$ .

The expression used for the calculation of $pK_a$ is,

$pK_a=-\log (K_a)$

Now put the value of $K_a$ in this expression, we get:

$pK_a=-\log (1.8\times 10^{-5})$

$pK_a=5-\log (1.8)$

$pK_a=4.7$

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

$pH=pK_a+\log \frac{[CH_3CO_2K]}{[CH_3CO_2H]}$

Now put all the given values in this expression, we get:

$pH=4.7+\log (\frac{0.030}{0.10})$

$pH=4.2$

Therefore, the pH of the solution is, 4.2

8 0

3 years ago