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Bumek [7]
3 years ago
5

You make the following measurements of an object – 22 kg and 42 m3. What would the object’s density be? Show your work for credi

t and include final units.
Chemistry
2 answers:
Dafna11 [192]3 years ago
4 0
Density = mass / volume
therefore, density = 22/42 = 0.524 kg/m3
Nat2105 [25]3 years ago
4 0

Answer: 0.52kgm^{-3}

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{volume}

We are given : Mass of an object = 22 kg

Volume of an object = 42m^3

Putting in the values in the formula for density:

Density=\frac{22kg}{42m^3}=0.52kgm^{-3}

Thus the mass has density of 0.52kgm^{-3} in S.I units.

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DochEvi [55]

Answer:

34.3 g

Explanation:

Step 1: Write the balanced equation

2 CH₃CH₂OH ⇒ CH₃CH₂OCH₂CH₃ + H₂O

Step 2: Calculate the moles corresponding to 50.0 g of CH₃CH₂OH

The molar mass of CH₃CH₂OH is 46.07 g/mol.

50.0 g × 1 mol/46.07 g = 1.09 mol

Step 3: Calculate the theoretical moles of CH₃CH₂OCH₂CH₃ produced

The molar ratio of CH₃CH₂OH to CH₃CH₂OCH₂CH₃ is 2:1. The moles of CH₃CH₂OCH₂CH₃ theoretically produced are 1/2 × 1.09 mol = 0.545 mol.

Step 4: Calculate the real moles of CH₃CH₂OCH₂CH₃ produced

The percent yield of the reaction is 85%.

0.545 mol × 85% = 0.463 mol

Step 5: Calculate the mass corresponding to 0.463 moles of CH₃CH₂OCH₂CH₃

The molar mass of CH₃CH₂OCH₂CH₃ is 74.12 g/mol.

0.463 mol × 74.12 g/mol = 34.3 g

6 0
3 years ago
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A. True <br> b. False a chemical species is either an acid or a base, it cannot function as both
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