Question

1.8 A water flow of 4.5 slug/s at 60 F enters the condenser of steam turbine and leaves at 140 F. Determine the heat transfer rate (Btu/hr)

Answer 1

Answer:

$Hr=4.2*10^7\ btu/hr$

Explanation:

From the question we are told that:

Water flow Rate $R=4.5slug/s=144.78ib/sec$

Initial Temperature $T_1=60 \textdegree F$

Final Temperature  $T_2=140 \textdegree F$

Let

Specific heat of water $\gamma= 1$

And

 $\triangle T= 140-60$

 $\triangle T= 80\ Deg.F$

Generally the equation for Heat transfer rate of water  $H_r$ is mathematically given by

Heat transfer rate to water= mass flow rate* specific heat* change in temperature

 $H_r=R* \gamma*\triangle T$

 $H_r=144.78*80*1$

 $H_r=11582.4\ btu/sec$

Therefore

 $H_r=11582.4\ btu/sec*3600$

 $Hr=4.2*10^7\ btu/hr$