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Alina [70]
3 years ago
14

30 km/h is _________m/s? A.)8.3 B.)5.6 C.)13.9 D.)11.1

Physics
1 answer:
Juli2301 [7.4K]3 years ago
3 0

Answer:

Correct  Option :-  A

Explanation:

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Need answer ASAP!!!
Alina [70]

Hello!

Use <u>ohm law:</u>

I = V / R

Replacing:

I = 100 V / 20 O

I = 5 A

The current is <u>5 amperes.</u>

5 0
3 years ago
If an automobile's velocity changes from 25 m/s to 15m/s in 2s, then what is its acceleration?
tekilochka [14]
Hey!

u=25m/s
v=15m/s
t=2s
a=?

v-u=at
15-25=a×2
-10=2a
-10/2=a
a=-5m/s^2

Hope it helps...!!!
8 0
4 years ago
Because ions in an ionic crystal are tightly bound together, _____. it takes little energy to change them from a solid to a liqu
umka2103 [35]
Ions are particles formed when an atom of an element looses or gains electrons to attain a stable configuration.They are either positively charged (cations) or negatively charged (anions). Ionic crystals consists of ions bound together by electrostatic attraction forming a regular arrangement, geometric structure called crystal lattice. In an ionic solid the ions are held by strong attractive forces (tightly bound) and cannot move from their positions in the crystal structure and  therefore, do not conduct electricity.
7 0
3 years ago
Find the wavelength of the balmer series spectral line corresponding to n = 15.
Anna71 [15]

Answer:

371.2 mm

Explanation:

The Balmer series of spectral lines is obtained from the formula

1/λ = R(1/2² -1/n²) where λ = wavelength, R = Rydberg's constant = 1.097 × 10⁷ m⁻¹

when n = 15

1/λ = 1.097 × 10⁷ m⁻¹(1/2² -1/15²)

    = 1.097 × 10⁷ m⁻¹(1/4 -1/225)

    = 1.097 × 10⁷ m⁻¹(0.25 - 0.0044)

    = 1.097 × 10⁷ m⁻¹ 0.245556

    = 2.693 10⁶ m⁻¹

So,

λ  = 1/2.693 10⁶ m⁻¹

    = 0.3712 10⁻⁶ m

    = 371.2 mm

7 0
3 years ago
A flat, 181 ‑turn, current‑carrying loop is immersed in a uniform magnetic field. The area of the loop is 4.97 cm2 and the angle
Sidana [21]

Answer:

B = 0.135T

Explanation:

To find the magnitude of the magnetic field you use the following formula, for the torque produced by a magnetic field B in a loop:

\tau=NIABsin\theta   (1)

τ: torque = 1.51*10^-5 Nm

I: current = 2.47mA = 2.47*10^-3 A

B: magnitude of the magnetic field

A: area of the loop = 4.97cm^2 = 4.97(10^-2m)^2=4.97*10^-4m^2

N: turns = 181

θ: angle between B and the magnetic dipole (same as the direction  of the normal to the plane)

You replace the values of the parameters in (1). Furthermore you do B the subject of the formula:

B=\frac{\tau}{NIAsin\tetha}=\frac{1.51*10^{-5}Nm}{(181)(2.47*10^{-3}A)(4.97*10^{-4}m^2)(sin30.1\°)}=0.135T

3 0
3 years ago
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