I'm quite certain the answer is "stress".
Answer:
Force / mass
Explanation:
Divide mass on both sides to get acceleration by itself leaving you with mass below force hence divide force by mass
Answer:
170N
Explanation:
First add 530N to 150N and you get 680N, then add 400N to 450N and get 850N. So subtract 850N by 680N and you get 170N
Answer:
The ratio is
Explanation:
From the question we are told that
The radius of Phobos orbit is R_2 = 9380 km
The radius of Deimos orbit is ![R_1 = 23500 \ km](https://tex.z-dn.net/?f=R_1%20%20%3D%20%2023500%20%5C%20%20km)
Generally from Kepler's third law
![T^2 = \frac{ 4 * \pi^2 * R^3}{G * M }](https://tex.z-dn.net/?f=T%5E2%20%3D%20%20%5Cfrac%7B%204%20%2A%20%20%5Cpi%5E2%20%2A%20%20R%5E3%7D%7BG%20%2A%20M%20%20%7D)
Here M is the mass of Mars which is constant
G is the gravitational constant
So we see that ![\frac{ 4 * \pi^2 }{G * M } = constant](https://tex.z-dn.net/?f=%5Cfrac%7B%204%20%2A%20%20%5Cpi%5E2%20%20%7D%7BG%20%2A%20M%20%20%7D%20%3D%20%20constant)
=> ![[\frac{T_1}{T_2} ]^2 = [\frac{R_1}{R_2} ]^3](https://tex.z-dn.net/?f=%5B%5Cfrac%7BT_1%7D%7BT_2%7D%20%5D%5E2%20%3D%20%20%5B%5Cfrac%7BR_1%7D%7BR_2%7D%20%5D%5E3)
Here
is the period of Deimos
and
is the period of Phobos
So
![[\frac{T_1}{T_2} ] = [\frac{R_1}{R_2} ]^{\frac{3}{2}}](https://tex.z-dn.net/?f=%5B%5Cfrac%7BT_1%7D%7BT_2%7D%20%5D%20%3D%20%20%5B%5Cfrac%7BR_1%7D%7BR_2%7D%20%5D%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D)
=> ![\frac{T_1}{T_2} = [\frac{23500 }{9380} ]^{\frac{3}{2}}]](https://tex.z-dn.net/?f=%5Cfrac%7BT_1%7D%7BT_2%7D%20%20%3D%20%20%5B%5Cfrac%7B23500%20%7D%7B9380%7D%20%5D%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%5D)
=>
Answer:
The correct option is;
a- sea surface temperature anomaly, in degrees Celsius
Explanation:
From the diagram related to the question we have two graphs super imposed of Sea surface temperature anomaly, in degrees Celsius and cholera incidence anomaly (%) both plotted against time in years.
On the left the y-axis represents the sea surface temperature anomaly while on the right, the y-axis represents the cholera incidence anomaly (%).
The display of the graph shows the sea surface temperature anomaly in blue.