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mario62 [17]
2 years ago
15

Charlotte is driving at 66.5 mi/h and receives a text message. She looks down at her phone and takes her eyes off the road for 3

.47 s. How far has Charlotte traveled in feet during this time
Physics
1 answer:
Alborosie2 years ago
7 0

Answer:

the distance traveled by Charlotte in feet is 338.44 ft

Explanation:

Given;

speed of Charlotte, u = 66.5 mi/h

time of motion, t = 3.47 s

The distance traveled by Charlotte in feet is calculated as;

Distance = Speed \ \times \ time \\\\D = ut\\\\D = (\frac{66.5 \ mi}{h} \times  \frac{5280 \ ft}{1 \ mi} \times \frac{1 \ h}{3600 \ s} )(3.47 \ s)\\\\D = 338.44 \ ft

Therefore, the distance traveled by Charlotte in feet is 338.44 ft

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STALIN [3.7K]
In lakes and streams
5 0
3 years ago
24 POINTS!!!!!!!!!!!!!!!
TEA [102]
Potential Energy (Initial one) = m * g * h
P.E. = 60 * 9.8 * 10
P.E. = 5880

Kinetic Energy (Final One) = 1/2 mv²
K.E. = 1/2 * 60 * (10)²
K.E. = 6000/2
K.E. = 3000

Lost Energy = 5880 - 3000 = 2880 J

In short, Your Answer would be 2880 Joules

Hope this helps!
7 0
2 years ago
Read 2 more answers
In creating his definition of horsepower, James Watt, the inventor of the steam engine, calculated the power output of a horse o
Studentka2010 [4]

Answer:

Part a)

F = 182.3 Lb

Part b)

P = 0.55 HP

Explanation:

Diameter of the circle = 24 ft

Diameter = 731.52 cm = 7.3152 m

now the horse complete 144 trips in one hour

so time to complete one trip is given as

t = \frac{3600}{144} s

t = 25 s

now the speed of the horse is given as

v = \frac{2\pi r}{t}

v = \frac{\pi(7.3152)}{25}

v = 0.92 m/s

Part a)

Now we know that the power is defined as rate of work done

it is given as

P = F v

746 = F(0.92)

F = 810.9 N

F = 182.3 Lb

Part b)

Work done to climb up to 3 m height is given by

W = mgh

now we have

Power = \frac{Work}{time}

P = \frac{mgh}{t}

P = \frac{(70kg)(9.81)(3)}{5.0s}

P = 412.02 Watt

now we know that 1 HP = 746 Watt

so we have

P = \frac{412}{746} = 0.55 HP

8 0
2 years ago
HELP ME
sergij07 [2.7K]

Answer:

13,308 MAYBE IF IT ISN'T IM SO SORRY

Explanation:

6 0
2 years ago
Calculate the mass of an ice block of volume 12m³. the density of the ice is 920kg/m³.​
beks73 [17]

Mass = density • volume

so (12)(920)(kg/m^3•m^3)

11040 kg

4 0
2 years ago
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