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1 year ago

Construct a quadrilateral MINT such that MI= 5cm, IN = 6cm, NT = 7cm, TM=3cm and MN =9cm

Mathematics

1 answer:

Tems11 [23]1 year ago

6 0

From the given dimensions, of MI, IN, NT, TM, and MN, the quadrilateral

MINT can be drawn as shown in the attached image.

<h3>What are the steps for the construction of MINT?</h3>

The given dimensions of the quadrilateral MINT are;

MI = 5 cm

IN = 6 cm

NT = 7 cm

TM = 3 cm

MN = 9 cm

The side MN is a diagonal of MINT, therefore;

ΔMIN, and ΔMTN are triangles with a common base = MN

The steps to construct MINT are therefore;

Step 1; Draw the line MN = 9 cm.

Step 2; Place the compass at point <em>M</em> and with a radius MI = 5 cm, draw an arc on one side of MN.

Step 3; Place the compass at <em>N</em> and with radius IN = 6 cm, draw an arc to intersect the arc dawn in step 1 above.

Step 4; Place an arc at point <em>M</em> and with radius TM = 3 cm draw an arc on the other side of MN.

Step 5; Place the compass at point <em>N</em> and with radius NT = 7 cm, draw an arc to intersect the arc drawn in step 3.

Step 6; Join the point of intersection of the arcs to points <em>M</em> and <em>N</em> to complete the quadrilateral MINT.

Please find attached the drawing (showing the construction arcs) of the

quadrilateral MINT created with MS Word.

Learn more about types of geometric construction here:

brainly.com/question/785568

brainly.com/question/8607612

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Harlamova29_29 [7]

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<h3>How to identify the maximums of function h(x)?</h3>

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2 years ago

1 Select the correct answer. Multiply the binomials: (3x + 4)(5x - 2) A.15x2 + 20x-8b. 15x2 + 14x-8 c. 15x2- 14x-8 D. 15x2+ 14x8

leonid [27]

Multiply the binomials:

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Final answer

Option B is the final answer

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1 year ago

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Strike441 [17]

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Sphinxa [80]

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