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dexar [7]
2 years ago
9

Topics:

Physics
1 answer:
spin [16.1K]2 years ago
3 0

I need you to make me an invented poem written please not in image

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In a computer-based experiment to study diffraction, the width of the central diffraction peak is 15.20 mm. The wavelength of th
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Answer:

a = 5.7 \times 10^{-5} m

Explanation:

As we know that position of first minimum on the either side of central maximum is given as

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so we have

15.20 \times 10^{-3} = 0.68 \times 2(sin^{-1} \frac{\lambda}{a})

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0.011 = sin^{-1} \frac{\lambda}{a}

0.011 = \frac{638 nm}{a}

a = 5.7 \times 10^{-5} m

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