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mr Goodwill [35]
3 years ago
14

How did the work of Dmitri Mendeleev differ from that of John Newlands in the development of the periodic table?

Chemistry
1 answer:
alex41 [277]3 years ago
3 0
When Newlands tried to create a periodic table, his tried to conform to the "Rule of Octaves" he had discovered. He had the right idea, in that if you arrange the elements by atomic weight there would be similarities every 7 elements (not 8 because noble gases hadn't been discovered yet) but he tried to push this rule so much that he would put multiple elements in the same box to try to keep the rule. Mendeleev, however, left gaps in this table for undiscovered elements, which paved the way for our modern periodic table.
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3 years ago
A gas occupying a volume of 656.0 mL at a pressure of 0.884 atm is allowed to expand at constant temperature until its pressure
7nadin3 [17]

Answer:

1.14 × 10³ mL

Explanation:

Step 1: Given data

  • Initial volume of the gas (V₁): 656.0 mL
  • Initial pressure of the gas (P₁): 0.884 atm
  • Final volume of the gas (V₂): ?
  • Final pressure of the gas (P₂): 0.510 atm

Step 2: Calculate the final volume of the gas

If we assume ideal behavior, we can calculate the final volume of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 0.884 atm × 656.0 mL/0.510 atm = 1.14 × 10³ mL

5 0
3 years ago
How do you determine the chemical reactivity for metals using the periodic table?
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8 0
3 years ago
What are the highest-frequency and lowest-frequency parts of the EM spectrum
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4 0
2 years ago
If a 0.4681 g Mg strip reacts with 0.650 M HCl in a 139.3 mL flask at 25oC, what is the minimum volume (mL) of HCl needed to com
Marizza181 [45]
The reaction between the magnesium, Mg, and the hydrochloric acid, HCl is given in the equation below,

    Mg + 2HCl --> H2 + MgCl2

The number of moles of HCl that is needed for the reaction is calculated below.
    n = (0.4681 g Mg)(1 mol Mg/24.305 g Mg)(2 mol HCl/1 mol Mg)
    n = 0.0385 mols HCl

From the given concentration, we calculate for the required volume. 
    V = 0.0385 mols HCl/(0.650 mols/L)
     V = 0.05926 L or 59.26 mL

<em>Answer: 59.26 mL of HCl</em>
7 0
3 years ago
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