X = jane, y = jasmine, z = jocelyn
x + y + z = 56
x = 3z
y = 2z + 2
3z + 2z + 2 + z = 56
6z + 2 = 56
6z = 56 - 2
6z = 54
z = 54/6
z = 9 <==== jocelyn
x = 3z
x = 3(9)
x = 27 <=== jane
y = 2z + 2
y = 2(9) + 2
y = 18 + 2
y = 20 <=== jasmine
One solution was found :
x = ∛15 = 2.466
Step by step solution :
Step 1 :
12÷x2
Equation at the end of step 1 :
3 12
(((((3x-————)+6x)-27)-2x)-——)-(6x-27) = 0
(x2) x2
Step 2 :
3÷ x2
Equation at the end of step 2 :
3 12
(((((3x-——)+6x)-27)-2x)-——)-(6x-27) = 0
x2 x2
1) so soo si Suu si sh Djibouti Di RI du du sh sh sh db dc xv CNN CNN b b hm
Answer:
h=−6, k=−30
Step-by-step explanation:
did on edge
Answer:
x = 10
Step-by-step explanation:
x = 10
