Answer:
imma go with the answer B
Answer:
The heat absorbed by water is 39243.75 J.
Explanation:
Given data:
Mass of water = 375.0 g
Heat absorbed by water= ?
Initial temperature = 10.0°C
Final temperature = 35.0 °C
The specific heat capacity of water = 4.186 j/g.°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 35°C - 10°C
ΔT = 25°C
Q = m.c. ΔT
Q = 375.0 g× 4.186 j/g °C × 25°C
Q = 39243.75 J
The heat absorbed by water is 39243.75 J.
NO
The speed/.velocity will be decreasing
Explanation:
Acceleration is defined by the following equation;
a = delta-V / delta-T
Whereby;
A = acceleration
Delta-V= change in Velocity
T = change in Time
In ouer case we are sure that the value of a is negative because acceleration is decreasing. On the other hand, change in time is positive in our case because time is increasing (i.e moving forward)
Therefore to achieve a negative a (i.e -a), the delta-V must be negative;
Delta-v = V (final) – V (initial)
For a negative delta-V to be achieved, then the final velocity must be lower than the initial velocity
Learn More:
For more on acceleration equations check out;
brainly.com/question/1852158
brainly.com/question/12904893
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