Answer:
Al + 4AgNO3 >>Al(NO3)3+ 3Ag
Explanation:
the number of moles of No3 of the products is 3 therefore we have to balance the reactants by adding 3 before the "AgNO3" which also leades us to adding 3 mols to Ag on the products side
Hello Lilsavage717, I believe the answer you are looking for is C. or Amino Acids. They are mainly located in living things like plants or bugs.
The Intermolecular force is a type of force which exists between particles in an Ideal gas.
<h3>What type of force which exists between particles in an Ideal gas?</h3>
Intermolecular forces are considered weaker attractions that hold molecules in gas close together. This force of attraction is present between molecules or particles.
So we can conclude that the Intermolecular force is a type of force which exists between particles in an Ideal gas.
Learn more about attraction here: brainly.com/question/1308963
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Answer : The reagent present in excess and remains unreacted is, 
Solution : Given,
Moles of
= 3.00 mole
Moles of
= 2.00 mole
Excess reagent : It is defined as the reactants not completely used up in the reaction.
Limiting reagent : It is defined as the reactants completely used up in the reaction.
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,

From the balanced reaction we conclude that
As, 2 moles of
react with 1 mole of 
So, 3.00 moles of
react with
moles of 
From this we conclude that,
is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Hence, the reagent present in excess and remains unreacted is, 
Answer:
Final volume is 3.50L
Explanation:
It is possible to find volume of a gas using combined gas law:

<em>Where P is pressure, V is volume and T is temperature of 1: initial state and 2: final state</em>
If initial state of the gas is:
1.75L of a gas is at 700K and is under 250kPa of pressure
And final state is:
298K and 53.2kPa.
Replacing:

0.625L = 0.1785*V₂
<em>3.50L = V₂</em>
Thus, <em>final volume is 3.50L</em>