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Bond [772]
3 years ago
11

Which of the following is an example of using creativity while trying to explore scientific questions?

Chemistry
2 answers:
Mars2501 [29]3 years ago
4 0

Answer:

A. Thinking of various research methods

Explanation:

Thinking of various research methods is a creative endeavor. Different research methods can be time consuming, require the use of unique chemicals and special equipment, certain methods could be cumbersome or technically difficult to execute with high chances of failure etc. Also the researcher has to think about the independent and dependent variables and the control.

Law Incorporation [45]3 years ago
3 0

Your answer is correct!

The ability to come up with various alternatives based on a given set of conditions is one of the applications of creativity.

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Of the elements: b, c, f, li, and na. the element with the smallest ionization energy is
love history [14]
B-  8.2980
C-  11.2603
F-  17.4228
Li-  5.3917
Na- 5.1391

I would say your answer is Na.
8 0
3 years ago
Suppose that in an ionic compound, "m" represents a metal that could form more than one type of ion. in the formula mf2 , the ch
geniusboy [140]
F (Fluorine) is in column (group/family) VIIA, or the "halogens". When you see the halogens (Fluorine, Chlorine, Bromine, and Iodine) in combination with a metal, each halogen atom present will carry a -1 charge. We can see that the atom has no charge, so the metal must cancel out the negative charges brought by the two fluorine atoms.
(Charge on m) + 2*(charge on fluorine) = 0
(Charge on m) + 2*(-1) = 0
(Charge on m) - 2 = 0
Charge on m ion = +2
3 0
3 years ago
Water is a good solvent when A) the solute is hydrophobic. B) the solute is nonpolar. C) the solute is polar. D) the solvent is
pochemuha

the answer is C. the solute polar  water itself is a polar solvent so it combines well with other polar solvents (which basically have polar molecules)

8 0
3 years ago
0.58 mol of Mg contains how many atoms? please show work
Jet001 [13]

The number of atoms present in 0.58 mole of magnesium, Mg is 3.49×10²³ atoms

<h3>Avogadro's hypothesis </h3>

1 mole of Mg = 6.02×10²³ atoms

<h3>How to determine the atoms in 0.58 mole of Mg </h3>

1 mole of Mg = 6.02×10²³ atoms

Therefore,

0.58 mole of Mg = 0.58 × 6.02×10²³

0.58 mole of Mg = 3.49×10²³ atoms

Thus, 3.49×10²³ atoms are present in 0.58 mole of Mg

Learn more about Avogadro's number:

brainly.com/question/26141731

#SPJ1

3 0
2 years ago
What is the concentration of a solution with a volume of 660L that contains 33.4g of AlCO3?
lana [24]

Answer:

The concentration of the solution is 5.8168 × 10^{-4} mol.dm^{-3}

Explanation:

Here, we want to calculate the concentration of the solution.

The unit of this is mol/dm^3

So the first thing to do here is to calculate the number of moles of the solute present, which is the number of moles of AlCO3

The number of moles = mass/molar mass

molar mass of AlCO3 = 27 + 12 + 3(16)  = 27 + 12 + 48 = 87g/mol

Number of moles = 33.4/87 = 0.384 moles

This 0.384 moles is present in 660 L

x moles will be present in 1 dm^3

Recall 1 dm^3 = 1L

x * 660 = 0.384 * 1

x = 0.384/660 = 0.00058168 = 5.8168 * 10^-4 mol/dm^3

7 0
2 years ago
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