Answer:
X''(2, -5), Y''(3, -3)
Step-by-step explanation:
You know that reflection in the x-axis changes the sign of the y-coordinate. Points that used to be above the axis are now below by the same amount, and vice versa.
Rotation counterclockwise by 270° is the same as clockwise rotation by 90°. That maps the coordinates like this:
(x, y) ⇒ (y, -x)
The two transformations together give you ...
(x, y) ⇒ (x, -y) ⇒ (-y, -x) . . . . . . . . equivalent to reflection across y=-x.
Using this mapping, we have ...
X(5, -2) ⇒ X''(2, -5)
Y(3, -3) ⇒ Y''(3, -3) . . . . . . on the equivalent line of reflection, so invariant
_____
The attachment shows the original segment in red, the reflected segment in purple, and the rotated segment in blue. The equivalent line of reflection is shown as a dashed green line.
a. Parameterize
by

with
.
b/c. The line integral of
over
is




d. Notice that we can write the line integral as

By Green's theorem, the line integral is equivalent to

where
is the triangle bounded by
, and this integral is simply twice the area of
.
is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.
Answer:
<em>No </em><em>9</em><em>7</em><em> </em><em>is </em><em>not </em><em>an </em><em>irrational </em><em>number </em>
Step-by-step explanation:
Be happy
Answer:
John is 9 and Olivia is 12
Step-by-step explanation:
12+18= 20
36+ (9x8)= 108
Answer:
a.
and 41.6
b. 52.1
Step-by-step explanation:
a.
Considering the left side triangle the blue dotted side is the side "opposite" to the angle given and the side 24 is the side that is "adjacent" to the angle given. The trigonometric ratio tan relates opposite to adjacent. Also, let the blue dotted side be y.
<u>Note:</u> the exact value of tan 60 is 
Thus, we can write 
Approximate value (rounded to nearest tenth): 
b.
Considering the triangle to the right, the side "opposite" to the angle given (53 degrees) is 41.6 (just found in part (a)) and the side "hypotenuse" (side opposite to 90 degree angle) is x. The trigonometric ratio sine relates opposite and hypotenuse.
Thus we can write and solve:
