The answer to this question is:
A circle is growing so that the radius is increasing at the rate of 2cm/min. How fast is the area of the circle changing at the instant the radius is 10cm? Include units in your answer.?
✔️I assume here the linear scale is changing at the rato of 5cm/min
✔️dR/dt=5(cm/min) (R - is the radius.... yrs, of the circle (not the side)
✔️The rate of area change would be d(pi*R^2)/dt=2pi*R*dR/dt.
✔️At the instant when R=20cm,this rate would be,
✔️2pi*20*5(cm^2/min)=200pi (cm^2/min) or, almost, 628 (cm^2/min)
Hoped This Helped, <span>Cello10
Your Welcome :) </span>
Answer:
8 + 2n = 42
Step-by-step explanation:
the sum of eight: ___+ 8
and twice(2) a number(could be any variable but for now i choose n): <u>2n</u> + 8
is 42 (literally mean it equals 42): <u>2n</u> + 8 = 42
45 should be the answer for that specific question.
Answer:
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Step-by-step explanation:
