Answer:
So it will lift the mass by h = 17 m
Explanation:
As per energy conservation we know that

here we know that


now we have


so work done by the engine is 250 J
now we have



Given Information:
Charge = q = 7.0x10⁻⁶ C
Required Information:
Number of electrons = n = ?
Answer:
Number of electrons = 4.375x10¹³
Explanation:
We know that charge is given by
q = n*e
Where n is the number of electrons and e is the electronic charge that is 1.60x10⁻¹⁹ C
n = q/e
n = 7.0x10⁻⁶/1.60x10⁻¹⁹
n = 4.375x10¹³ electrons
Therefore, 4.375x10¹³ electrons were transferred.
Answer:
222.2N/m
Explanation:
Given parameters:
Elastic potential energy = 4000J
Extension = 6m
Unknown:
Spring coefficient = ?
Solution:
The elastic potential energy is the energy stored within a string.
It is expressed as;
EPE =
k e²
k is the spring constant
e is the extension
4000 =
x k x 6²
8000 = 36k
k = 222.2N/m
After years of observation, Hubble made an extraordinary discovery. In 1923 he spotted a Cepheid variable star in what was known as the Andromeda Nebula. Using Leavitt's techniques, he was able to show that Andromeda was nearly 1 million light years away and clearly a galaxy in its own right, not a gas cloud.
I think it would be near the sun due.to high rays of sun