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professor190 [17]
2 years ago
12

Find the product and simplify. (3c-5) ^2

Mathematics
2 answers:
alex41 [277]2 years ago
8 0

Hi!

<u>Given:</u>

(3c-5)^2

<u>As this is </u><u>squared</u><u>, we are simply </u><u>multiplying</u><u> the </u><u>given</u><u> </u><u>expression</u><u> by </u><u>itself</u><u>, like so:</u>

(3c-5)(3c-5)

<u>Now, we can use the </u><u>Distributive</u><u> </u><u>Property</u><u> to solve, using the </u><u>FOIL</u><u> </u><u>Method</u><u>:</u>

(3c-5)(3c-5)

9c^2-15c-15c+25

<u>Combine like terms:</u>

9c^2-30c+25

<u>For a similar problem, see:</u>

brainly.com/question/15639394

RSB [31]2 years ago
7 0

Answer:

9c² -30c + 25

Step-by-step explanation:

Perfect square trinomial: (a - b)² = a² - 2ab + b²

(3c - 5)²

(3c)² -2(3c * 5) + 5²

9c² -2(15c) + 5²

9c² -30c + 25

Final answer: 9c² -30c + 25

Hope this helps!

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B(n) = -1 (2)^n-1 What is the 5th term in the sequence?
bija089 [108]

Answer:

<h2>The answer is - 16</h2>

Step-by-step explanation:

<h3>b(n) =  - 1 ({2})^{n - 1}</h3>

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From the question since we are finding the 5th term

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hence the arithmetic sequence is

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3 years ago
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We need to use the calculator, using the tan⁻¹ function:

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