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1 year ago

Find the product and simplify. (3c-5) ^2

Mathematics

2 answers:

alex41 [277]1 year ago

8 0

Hi!

Given:

$(3c-5)^2$

As this is squared, we are simply multiplying the given expression by itself, like so:

$(3c-5)(3c-5)$

Now, we can use the Distributive Property to solve, using the FOIL Method:

$(3c-5)(3c-5)$

$9c^2-15c-15c+25$

Combine like terms:

$9c^2-30c+25$

For a similar problem, see:

brainly.com/question/15639394

RSB [31]1 year ago

7 0

Answer:

9c² -30c + 25

Step-by-step explanation:

Perfect square trinomial: (a - b)² = a² - 2ab + b²

(3c - 5)²

(3c)² -2(3c * 5) + 5²

9c² -2(15c) + 5²

9c² -30c + 25

Final answer: 9c² -30c + 25

Hope this helps!

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1 year ago

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Step-by-step explanation:

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2 years ago

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Tju [1.3M]

Answer:

$\displaystyle \frac{x^4 + 10x^3 + 25x^2 + 3x - 24}{x^2 + 5x - 4} = x^2 + 5x - 4 + \frac{3x - 8}{x^2 + 5x - 4}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding

Algebra II

Polynomial Division

Long Division
Synthetic Division

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle \frac{x^4 + 10x^3 + 25x^2 + 3x - 24}{x^2 + 5x - 4}$

Step 2: Long Division

See attachment.

Multiply quotient a and divisor, then subtract from dividend: $\displaystyle x^2(x^2 + 5x - 4) = x^4 + 5x^3 - 4x^2 \leftarrow \text{red 1}$
Multiply quotient b and divisor, then subtract from new dividend: $\displaystyle 5x(x^2 + 5x - 4) = 5x^3 + 25x^2 - 20x \leftarrow \text{red 2}$
Multiply quotient c and divisor, then subtract from new dividend: $\displaystyle 4(x^2 + 5x - 4) = 4x^2 + 20x - 16 \leftarrow \text{red 3}$
Write remainder: $\displaystyle \frac{r(x)}{b(x)} = \frac{3x - 8}{x^2 + 5x - 4}$

Please excuse the bad handwriting.

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1 year ago