A crate with a mass of 175.5 kg is suspended from the end of a uniform boom with a mass of 94.7 kg. The upper end of the boom is
supported by a cable attached to the wall and the lower end by a pivot (marked X) on the same wall.
Calculate the tension in the cable.
Calculate the tension in the cable.
1 answer:
The tension in the cable is mathematically given as
T =266.659 N
<h3>What is the tension in the cable.?</h3>Generally, the equation for the angle of the boom with horizontal is mathematically given as
A = tan-1(5 /10)
The angle of cable with horizontal
B = tan-1(4 / 10)
B= 21.80 degrees
Hence
175.5 * cos26.57 + 94.7 *cos26.57 * 1/2 = T (sin(26.57+21.80)) * 1
T =266.659 N
In conclusion, the tension in the cable.
T =266.659 N
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= 2.5
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