According to the saving of the momentum, the total momentum before collision is equal to the total momentum after collision
<em><u>in symbols:</u></em>
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thus
then, the initial momentum of the second cart
Answer:
work done is 470400 J
Explanation:
given data
long = 3 m
wide = 2 m
deep = 4 m
density = 1000 kg/m³
to find out
Find the amount of work in joules
solution
we know here volume = area × length
so
area = 0.5 ×base×height
area = 0.5 ×2×4
area = 4 m²
so volume = 4 × 3 = 12 m³
and
weight of water = volume ×density×g
weight = 12 × 1000 × 9.8
weight = 117600 N
so
work done = weight × height
work done = 117600× 4
work done = 470400 J
Answer:
A. put water in a container under the pot water will disappear from the container .
Answer:
8 m/s² south
Explanation:
Given:
v₀ = 40 m/s
v = 0 m/s
Δx = 100 m
Find: a
v² = v₀² + 2a (x − x₀)
0² = 40² + 2a (100)
a = -8
The acceleration is 8 m/s² south.
Given Information:
Resistance = R = 1.9 k
Ω
Capacitance = C = 30 uF
Initial charge = 30 uC
Final charge = 5 uC
Required Information:
Time taken to reduce the capacitor's charge to 5.0 μC = ?
Answer:
t = 0.101 seconds
Explanation:
The voltage across the capacitor is given by
V = V₀e^(–t/τ)
Where τ is time constant, V₀ is the initial voltage, V is the voltage after some time t
τ = RC
τ = 1900*30x10⁻⁶
τ = 0.057 sec
The initial voltage across the capacitor was
V₀ = Q/C
V₀ = 30/30
V₀ = 1 V
Voltage to reduce the charge to 5 uF
V = 5/30
V = 0.167 V
V = V₀e^(–t/τ)
0.167 = 1*e^(–t/0.057)
take ln on both sides
ln(0.167) = ln(e^(–t/0.057))
-1.789 = -t/0.057
t = 1.789*0.057
t = 0.101 seconds
