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eimsori [14]
3 years ago
10

What makes the id different from the superego?

Physics
1 answer:
KATRIN_1 [288]3 years ago
3 0
The id is part of the unconscious mind, and the superego is always conscious.
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Which statement explains what happens to older crust during seafloor spreading?
ikadub [295]

Answer:

the last one, It moves away from a mid-ocean ridge.

6 0
2 years ago
A helium nucleus contains two protons and two neutrons. The mass of the helium nucleus is greater than the combined masses of tw
dsp73

Answer:

False

Explanation:

Actually, the converse is true. The mass number would be lower than the sum of the mass of the individual nucleons combined. According to Einstein’s equation of E=MC², this will be due to a phenomenon called mass defect. This ‘anomaly’ is due to the loss of some energy (now the nuclear binding energy) when the nucleons were brought in together to form the nucleus.

8 0
3 years ago
A frequency generator sends a 550Hz sound wave through both water and ice. What is the difference in wavelength between the wave
LUCKY_DIMON [66]

Answer:

3.1

Explanation:

use formula f = v/lambda

7 0
3 years ago
Two fans are watching a baseball game from different positions. One fan is located directly behind home plate, 18.3 m from the b
EleoNora [17]

Answer:

  • 0.317 s

Explanation:

distance of fan A = 18.3 m

distance of fan B = 127 m

speed of sound (s) = 343 m/s

What is the time difference between hearing the sound at the two locations?

time (T) = distance / speed

  • time for sound to reach fan A = 18.3 / 343 = 0.053 s
  • time it takes for sound to reach fan B = 127 / 343 = 0.370 s
  • time difference = 0.370 - 0.053 = 0.317 s
5 0
3 years ago
You push a 1.30 kg physics book 2.80 m along a horizontal tabletop with a horizontal push of 1.55 N while the opposing force of
Rzqust [24]

Answer:

<h2>3.36J</h2>

Explanation:

Step one:

given data

mass m= 1.3kg

distance moved s= 2.8m

opposing frictional force= 0.34N

assume g= 9.81m/s^2

we know that work done= force *distance moved

1. work done to push the book= 1.55*2.8=4.34J

2. Work against friction = force of friction x distance

                                       = 0.34*2.8=0.952J

Step two:

the work done on the book is the net work, which is

Network done= work done to push the book- Work against friction

Network done= 4.32-0.952=3.36J

<u>Therefore the work of the 1.55N 3.36J</u>

4 0
2 years ago
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