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Luba_88 [7]
3 years ago
9

A hot spot is an area where material from deep within the mantle rises and melts through the crust above it. True or false need

help quick
Physics
2 answers:
fenix001 [56]3 years ago
8 0

It is true. Hope this helps.

FrozenT [24]3 years ago
3 0
True hope this helps
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a physics student throws a stone horizontally off a cliff. one second later, he throws a second identical stone in exactly the s
Virty [35]

The second stone hits the ground exactly one second after the first.

The distance traveled by each stone down the cliff is calculated using second kinematic equation;

h = v_0_yt + \frac{1}{2} gt^2

where;

  • <em>t is the time of motion </em>
  • <em />v_0_y<em> is the initial vertical velocity of the stone = 0</em>

h = \frac{1}{2} gt^2

The time taken by the first stone to hit the ground is calculated as;

t_1 = \sqrt{\frac{2h}{g} }

When compared to the first stone, the time taken by the second stone to hit the ground after 1 second it was released is calculated as

t_2 = \sqrt{\frac{2h}{g} } + 1

t_2 = t_1 + 1

Thus, we can conclude that the second stone hits the ground exactly one second after the first.

"<em>Your question is not complete, it seems be missing the following information;"</em>

A. The second stone hits the ground exactly one second after the first.

B. The second stone hits the ground less than one second after the first

C. The second stone hits the ground more than one second after the first.

D. The second stone hits the ground at the same time as the first.

Learn more here:brainly.com/question/16793944

8 0
3 years ago
Find the resistance of an electric light bulb if a current of 0.08 A flows when the potential difference across the bulb is 120
lora16 [44]
U=RI Ohm's law
then R=U/I
=120/0.08
=2250Ω
hope this helps you
8 0
3 years ago
Figure 1 shows a wave movement during one second. What is the frequency of the wave
Andreyy89
This is 2 hertz.  You can mark out 2 full wavelengths in the second of time.
4 0
3 years ago
Read 2 more answers
A boy pushes a cart with a constant velocity of 0.5m/s by applying a force of 60 N. What is the total frictional force acting on
Nutka1998 [239]

Answer:

60N

Explanation:

in this case the minimum amount of force required must be equal to the friction Force. i.e <u>Newton</u><u>'s</u><u> </u><u>first</u><u> </u><u>law</u><u> of</u><u> </u><u>mot</u><u>ion</u><u>.</u>

therefore the maximum amount of frictional force is equal to the applied force which is 60N.

because of the net force acting on the object is zero the object is in constant motion . i.e equal and opposite force must be applied so that the object is in constant velocity therefore the total frictional force must be 60N

8 0
3 years ago
A person is riding on a Ferris wheel. When the wheel makes one complete turn, the net work done on the person by the gravitation
lara31 [8.8K]

Answer:

0

Explanation:

m = Mass of person

g = Acceleration due to gravity = 9.81 m/s²

d = Vertical height from the ground

F = Force = Weight = mg

Net work done would be

W_n=W_{up}+W_{down}\\\Rightarrow W_n=Fdcos180+Fdcos0\\\Rightarrow W_n=-mgd+mgd\\\Rightarrow W_n=0

Hence, the work done on the person by the gravitational force is 0

7 0
3 years ago
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