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jek_recluse [69]
2 years ago
9

Please help me with this

Mathematics
1 answer:
motikmotik2 years ago
8 0
The answer is the 15
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Math thanks ik u like math
Mariulka [41]
Oh man maths hard ;( ...
6 0
3 years ago
Read 2 more answers
Substitute t=3 and t=5 to determine if the two expressions are equivalent.
motikmotik

Answer:

E

because both sides are equal when substituted by 3 & 5

4 0
2 years ago
F(x) = lnx/x
My name is Ann [436]
f(x) = \frac{lnx}{x}

(a) f'(x) = \frac{d}{dx}[\frac{lnx}{x}]
Using the quotient rule:
f'(x) = \frac{\frac{1}{x} \cdot x - lnx}{x^{2}}
f'(x) = \frac{1 - lnx}{x^{2}}

For maximum, f'(x) = 0;
\frac{1 - lnx}{x} = 0
lnx = 1, x = e

(b) <em>Deduce:
</em>e^{x} \geq x^{e}, x > 0
<em>
Soln:</em> Since x = e is the greatest value, then f(e) ≥ f(x) > f(0)
\frac{ln(e)}{e} \geq \frac{lnx}{x}
\frac{1}{e} \geq \frac{lnx}{x}, since ln(e) is simply equal to 1

Now, since x > 0, then we don't have to worry about flipping the signs when multiplying by x.
\frac{x}{e} \geq lnx
x \geq elnx
x \geq ln(x^{e})

Taking the exponential to both sides will cancel with the natural logarithmic function in the right hand side to produce:
e^{x} \geq e^{ln(x^{e}})
e^{x} \geq x^{e}, as required.
3 0
3 years ago
Jan's age is three years less than twice tritts age. The sum of their ages is 30. Find their ages.
Stells [14]
Jans age is 31 and tritts age is 35
3 0
3 years ago
Read 2 more answers
Xavier made 25 pounds of roasted almonds for a fair he has 3 and 1/2 pounds left at the end of the fair how many pounds of roast
Pepsi [2]

Answer:

Step-by-step explanation:

25-x=3 (1/2)

you just subtract 25 by 3 (1/2), and you get 21 (1/2).

Xavier sold 21 (1/2) pounds of roasted almonds

4 0
3 years ago
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