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2 years ago

QUICK!!

Physics

1 answer:

oee [108]2 years ago

3 0

Answer:

The distance between

Explanation:

F = G m1m2/r^2

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You want to make a ride so you do not want to exceed 1.1g’s, if the radius of the turns are 10m, then what is the maximum speed

Citrus2011 [14]

The maximum speed is 10.4 m/s

Explanation:

For a body in uniform circular motion, the centripetal acceleration is given by:

$a=\frac{v^2}{r}$

where

v is the linear speed

r is the radius of the circular path

In this problem, we have the following data:

- The maximum centripetal acceleration must be

$a=1.1 g$

where $g=9.8 m/s^2$ is the acceleration of gravity. Substituting,

$a=(1.1)(9.8)=10.8 m/s^2$

- The radius of the turn is

r = 10 m

Therefore, we can re-arrange the equation to solve for v, to find the maximum speed the ride can go at:

$v=\sqrt{ar}=\sqrt{(10.8)(10)}=10.4 m/s$

Learn more about centripetal acceleration:

brainly.com/question/2562955

#LearnwithBrainly

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4 years ago

Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy source

Alex_Xolod [135]

Answer:

The magnetic field strength required to hold anti-protons, moving at 5.70 ✕ 10⁷ m/s in a circular path of 3.20 m in radius is 0.186 T.

Explanation:

To solve the question we note that the magnetic force on a moving charge is given by

F = q·v·B

Where

q = Charge

v = Velocity of the charge =5.70 ✕ 10⁷ m/s

B = Magnetic field

Based on Newton's second law,

Force = Mass, m × Acceleration, a = m × a

Where:

a = Acceleration

m = Mass of anti-proton = Mass of proton = 1.6726219 × 10⁻²⁷ kg

We note that for circular motion, acceleration a is given by

$\alpha = \frac{v^{2} }{r}$ .

Where:

r = Radius = 3.20 m

Therefore, for the circular motion, force, F = $\frac{m\cdot v^{2} }{r}$

Equating the magnetic force equation to the circular force equation, we have

$\frac{m\cdot v^{2} }{r}$ = q·v·B So that, we find B by making the subject of the formula as follows

$B= \frac{m\times v^{2} }{r\times q \times v}$ . Which gives

$B= \frac{m\times v }{r\times q} = \frac{(1.6726219 \times 10^{-27}) \times (5.7\times 10^{7}) }{(3.20)\times (1.602\times 10^{-19}) }$ = 0.186 T

The magnetic field strength is

B = 0.186 T

4 0

3 years ago

Please help!!!!!!!!!!!!! i will give brainly

liq [111]

Answer:

1.) strength or energy to do an action or movement

2.)an object will jot change its motion unless acted on by an unbalanced force

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3 years ago

A 1 uF parallel-plate capacitor is charged to 12 V and then disconnected from the voltage supply. The plate separation distance

nlexa [21]

Answer:

Explanation:

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3 years ago

in order to generate electricity, nuclear powerplants take advantage of this part of the electromagnetic spectrum

antiseptic1488 [7]

Bit of an odd question. Power Plants are known to use water-powered turbines to generate electricity, but can also make use of nuclear fission.

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3 years ago