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2 years ago

Please help!!!!!!!!!!!!! i will give brainly

Physics

1 answer:

liq [111]2 years ago

8 0

Answer:

1.) strength or energy to do an action or movement

2.)an object will jot change its motion unless acted on by an unbalanced force

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A 9.5 V battery supplies a 3.5 mA current to a circuit for 7.0 h. Part A How much charge has been transferred from the negative

pychu [463]

Answer:

88.2 C

Explanation:

The current can be defined as the rate of flow of charge in a conductor.

The relation between charge current and time is given as

I = Q/T

I = current, Q= charge and T = time

that is ampere = coulomb / second

The amount of charge passed is from the negative to the positive terminal

shall be given by:

Q = I * t = 3.5mA * 7h * 3600s/h = 88.2 C

Note: take care of the units.

7 0

3 years ago

A rural mail carrier logged the mileage on the odometer at the start of the mail route as 31,500 miles. After 6.5 hours, the car

dusya [7]

Answer: $32.77\ mi/hr$

Explanation:

Given

Initially Reading on the odometer is $31,500\ miles$

Final reading on the odometer is $31,713\ miles$

Time taken is $t=6.5\ hr$

average velocity $=\dfrac{\text{Displacement}}{\text{time}}$

$v_{avg}=\dfrac{31713-31500}{6.5}$

$v_{avg}=\dfrac{213}{6.5}$

$v_{avg}=32.77\ mi/hr$

Thus the average velocity of mail truck is $32.77\ mi/hr$

8 0

3 years ago

Long periods of unusually low precipitation are called?

DiKsa [7]

I think it is called a drought but i would look it up

6 0

3 years ago

A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.10 104 rad/s to an angular speed of 3.14

Anestetic [448]

Answer:

3.63 s

Explanation:

We can solve the problem by using the equivalent SUVAT equations for the angular motion.

To find the angular acceleration, we can use the following equation:

$\omega_f^2 - \omega_i ^2 =2 \alpha \theta$

where

$\omega_f = 3.14\cdot 10^4 rad/s$ is the final angular speed

$\omega_i = 1.10 \cdot 10^4 rad/s$ is the initial angular speed

$\theta= 2.00 \cdot 10^4 rad$ is the angular distance covered

$\alpha$ is the angular acceleration

Re-arranging the formula, we can find $\alpha$ :

$\alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}=\frac{(3.14\cdot 10^4 rad/s)^2-(1.10\cdot 10^4 rad/s)^2}{2(2.00\cdot 10^4 rad)}=2.16\cdot 10^4 rad/s^2$

Now we want to know the time the bit takes starting from rest to reach a speed of $\omega_f=7.85\cdot 10^4 rad/s$ . So, we can use the following equation:

$\alpha = \frac{\omega_f-\omega_i}{t}$

where:

$\alpha=2.16\cdot 10^4 rad/s^2$ is the angular acceleration

$\omega_f = 7.85\cdot 10^4 rad/s$ is the final speed

$\omega_i = 0$ is the initial speed

t is the time

Re-arranging the equation, we can find the time:

$t=\frac{\omega_f-\omega_i}{\alpha}=\frac{7.85\cdot 10^4 rad/s-0}{2.16\cdot 10^4 rad/s^2}=3.63 s$

4 0

3 years ago

Read 2 more answers

PLEASE HELP! thxssss<br>

Cerrena [4.2K]

Answer:

D is correct

Explanation:

5 0

2 years ago