Answer:
2.877 m/s
Explanation:
According to the laws of conservation of linear momentum,
the momentum of the moving objects before impact is equal to the momentum of the objects after impact (Assuming no external forces were applied)
Let both players are tackled and moving in V velocity
- M and m - masses of the players
- U and u - velocities of them respectively (both velocities are towards east direction )
momentum before impact = momentum after impact
→MU + →mu = →(M+ m )v
91.5 * 2.73 + 63.5 * 3.09 = (91.5 + 63.5) * V
→V = 2.877 m/s (To East)
m1= mass 1 = 1.1 kg
Vi1 = initial velocity 1 = 2.7 m/s
m2= 2.4 kg
V2i = -1.9 m/s
We assume east as positive and west as negative.
Apply the formulas:
Vf1 = ?
Replacing:
Answer: 3.6 m/s west
The time of motion of the object at the given speed and distance is 4 seconds.
<h3>Time of motion of the object</h3>
The time of motion of the object is calculated as follows;
t = d/v
where;
- d is distance = 10 m
- v is speed = 2.5 m/s
- t is time of motion
t = 10/2.5
t = 4 s
Thus, the time of motion of the object at the given speed and distance is 4 seconds.
Learn more about time here: brainly.com/question/2854969
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wavelength =wavevelocity
--——————
Frequency
Frequency = 1/T => 1 / 6.73 = 0.1486
Wave velocity = L/T => 3.75 / 6.73 = 0.5572
Therefore, wave length = 0.5572/0.1486 = 3.75m
